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If xis a beta random variable with parameters aand b, show that

E[X]=aa+b

Var(X)=ab(a+b)2(a+b+1)

Short Answer

Expert verified

In general, find the kth moment and use it to calculate the mean and variance.

Step by step solution

01

Beta distribution

Density function,

f(x)=(+)()()x-1(1-x)-1

x0,1is to be zero.

EXk=xkf(x)dx=(+)()()01xkx-1(1-x)-1dx

=(+)()()01xk+-1(1-x)-1dx

So,

localid="1649485821665" EXk=(+)()()B(k+,)

=(+)()()(k+)()(k++)

02

Explanation

Fork=1

E(X)=(+)()(+1)(++1)

=(+)()伪螕()(+)(+)=+

For k=2

EX2=(+)()(+2)(++2)

=(+)()(+1)伪螕()(++1)(+)(+)

So,

Var(X)=EX2-E(X)2

=(+1)(++1)(+)-2(+)2

=(+1)(+)-2(++1)(++1)(+)2

=伪尾(++1)(+)2

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