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Poker dice is played by simultaneously rolling 5dice. Show that

(a) P{no two alike}

(b) P{one pair}

(c) P{two pair}

(d) P{three alike}

(e) P{full house}

(f) P{four alike}

(g) P{five alike}

Short Answer

Expert verified

Hence proved.

Step by step solution

01

Step 1

Since we are rolling 5 dice, the total number of events is65.

02

a) P{no two alike}

No two alike i.e. we want 5different numbers from 5dice.

There are 65ways to choose 5different numbers from 1to 6.

5!for rolling of 5different dice.

Thus, number of no two alike is 5!×65=720

Therefore, probability is 72065=.0962

03

b) P{one pair}

There are 61×52ways to choose a pair and 53×3!ways to choose which is not a pair.

Thus, number of one pair is61×52×53×3!=3600.

Therefore, probability is360065=.4630

04

c) P{two pair}

The number of two pairs is 62×52×32×41=1800.

Thus, probability is180065=.2315

05

d) P{three alike}

First choose common number and dice having common number then choose other two numbers from five choisces.

The number of three alike is 61×53×52×2!=1200.

Thus, probability is 120065=.1543

06

e) P{full house}

Full house is three alike with pair

The number of full house is 61×53×51=300.

Thus, probability is30065=.0386

07

f) P{four alike}

The number of four alike is 61×54×51=150.

Thus, probability is 15065=.0193

08

g) P{five alike}

The number of five alike is 61=6.

Thus, probability is665=.0008

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Most popular questions from this chapter

Consider Example5o, which is concerned with the number of runs of wins obtained whennwins and mlosses are randomly permuted. Now consider the total number of runs—that is, win runs plus loss runs—and show that

P(2kruns)=n-1k-1m-1k-1n+mnP(2k+1runs)=n-1km-1k-1+n-1k-1m-1kn+mn

Let E,F,and Gbe three events. Find expressions for the events so that, of E,F,and G,

(a)only Eoccurs;

(b)both EandG, but notF, occur;

(c) at least one of the events occurs;

(d) at least two of the events occur;

(e) all three events occur;

(f) none of the events occurs;

(g) at most one of the events occurs;

(h) at most two of the events occur;

(i) exactly two of the events occur;

(j)at most three of the events occur.

1. A cafeteria offers a three-course meal consisting of an entree, a starch, and a dessert. The possible choices are given in the following table:

Course
Choices
Entree
Chicken or roast beef
Starch
Pasta or rice or potatoes
Dessert
Ice cream or Jello or apple pie or a peach

A person is to choose one course from each category.

(a)How many outcomes are in the sample space?

(b)Let Abe the event that ice cream is chosen. How many outcomes are inA?

(c)Let Bbe the event that chicken is chosen. How many outcomes are inB?

(d)List all the outcomes in the eventAB.

(e)LetCbe the event that rice is chosen. How many outcomes are inC?

(f)List all the outcomes in the eventABC.

The game of craps is played as follows: A player rolls two dice. If the sum of the dice is either a2,3,or12, the player loses; if the sum is either a 7or an 11, the player wins. If the outcome is anything else, the player continues to roll the dice until she rolls either the initial outcome or a 7. If the 7comes first, the player loses, whereas if the initial outcome reoccurs before the 7appears, the player wins. Compute the probability of a player winning at craps.

Hint: Let Eidenote the event that the initial outcome is iand the player wins. The desired probability is ∑i=1212P(Ei). To compute P(Ei), define the events Ei,nto be the event that the initial sum is i and the player wins on the nth roll. Argue that

P(Ei)=∑n=1∞P(Ei,n)

There aren socks, 3which are red, in the drawer. What is the value of n if, when 2the socks are chosen randomly, the probability that they are both red is12?

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