91Ó°ÊÓ

A cafeteria offers a three-course meal consisting of an entree, a starch, and a dessert.

$3$Course meal has to be selected i.e$1$Entree, $1$starch, and $1$Dessert. For Entrees, we have$2$options of Chicken or Roasted Beef. For Starch, we have$3$options of Pasta, Rice, or Potatoes.

For dessert, we have $4$options Ice cream, Jello, apple pie, or a peach.

To calculate the no. of outcomes we have to find out the total no. of possible combinations of Entree, Starch, and Dessert. Total No. of ways to select$1$Entree from$2$Entree=$2\mathrm{Cl}=2$. Total No. of ways to select $1$Starch from $3$Starch$=3\mathrm{Cl}=3$. Total No. of ways to select$1$. Dessert from $4$Dessert$=4\mathrm{Cl}=4$. Total outcome=(No. of ways to select$1$Entree)(No. of ways to select $1$Starch) (No. of ways to select 1 Dessert). Total no. of the outcomelocalid="1649313824420" $=234=24$.

Total No. of ways to select Dessert$A=1$(Ice cream chosen). To calculate the no. of outcomes in $A$we have to find out the total no. of possible combinations of Entree and Starch. Total No. of ways to select $1$Entree from $2$Entree$=2\mathrm{Cl}=2$. Total No. of ways to select$1$Starch from$3\mathrm{Starch}=3\mathrm{Cl}=3$.

The total outcome in$\mathrm{A}=($(No. of ways to select Entree)(No. of ways to select Starch)(No. of ways to select Dessert). Total no. of the outcomelocalid="1649313847437" $=231=6$.

Total No. of ways to select Entree$=1$(Chicken chosen). To calculate the no. of outcomes in $B$we have to find out the total no. of possible combinations of Dessert and Starch. Total No. of ways to select $1$Dessert from$4$Dessert=$4\mathrm{Cl}=4$. Total No. of ways to select$1$starch from $3$Starch$=3\mathrm{Cl}=3$.

The total outcome in$B=$(No. of ways to select Entree)(No. of ways to select Starch)(No. of ways to select Dessert). Total no. of outcome=$134=12$.

Total No. of ways to select Entree$=1$(Chicken chosen). Total No. of ways to select Dessert $=1$(Ice Cream Chosen). To calculate the no. of outcomes in $AB$we have to find the ways of choosing Starch. Total No. of ways to select 1 Starch from 3 Starch$=3\mathrm{Cl}=3$.

The total outcome in$AB=$(No. of ways to select Entree)(No. of ways to select Starch)(No. of ways to select Dessert). Total no. of the outcome$=131=3$. Outcomes are->

localid="1649313866242" $AB=($Chicken, Pasta, Ice Cream), (Chicken, Rice, Ice cream), (Chicken, Potatoes, Ice Cream).

Total No. of ways to select Starch$=1$(Rice chosen). To calculate the no. of outcomes in $C$we have to find out the total no. of possible combinations of Dessert and Entree. Total No. of ways to select$1$Entree from$2$Entree=$2C1=2$. Total No. of ways to select$1$Dessert from$3$Dessert=$4Cl=4$.

The total outcome in$\mathrm{A}=($(No. of ways to select Entree)(No. of ways to select Starch)(No. of ways to select Dessert). Total no. of outcome=$2/4=8$.

Total No. of ways to select Starch$=1$(Rice chosen). Total No. of ways to select Entree$=1$(Chicken Chosen). Total No. of ways to select Dessert= $1$(Ice Cream).

The total outcome in $\mathrm{A}=($No. of ways to select Entree)(No. of ways to select Starch)(No. of ways to select Dessert). Total no. of outcome= $1\mathrm{l}=1.$Outcome=(Chicken, Rice, Ice Cream).