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An elementary school is offering 3 language classes: one in Spanish, one in French, and one in German. The classes are open to any of the 100 students in the school. There are 28 students in the Spanish class, 26 in the French class, and 16 in the German class. There are 12 students who are in both Spanish and French, 4 who are in both Spanish and German, and 6 who are in both French and German. In addition, there are 2 students taking all 3 classes. (a) If a student is chosen randomly, what is the probability that he or she is not in any of the language classes? (b) If a student is chosen randomly, what is the probability that he or she is taking exactly one language class? (c) If 2 students are chosen randomly, what is the probability that at least 1 is taking a language class?

Short Answer

Expert verified
(a) The probability of a student not in any language class is \(0.48\). (b) The probability of a student taking exactly one language class is \(0.32\). (c) The probability of at least one student taking a language class if two are chosen randomly is \(0.769697\).

Step by step solution

01

Identify the given information

The exercise provides us with the following information: - There are 100 students in the school. - There are 28 students in the Spanish class, 26 in the French class, and 16 in the German class. - There are 12 students who are in both Spanish and French, 4 who are in both Spanish and German, and 6 who are in both French and German. - There are 2 students taking all 3 classes.
02

Determine the number of students in each corresponding set

We should determine the number of students in each corresponding set without overlaps. Using the Principle of Inclusion and Exclusion, we have: - Students in Spanish class only: 28 - 12 - 4 + 2 = 14 - Students in French class only: 26 - 12 - 6 + 2 = 10 - Students in German class only: 16 - 4 - 6 + 2 = 8 - Students in only two classes: (12 + 4 + 6) - 3 * 2 = 18 - Students in all three classes: 2
03

Calculate the number of students in any language class and not in any language class

Add up the number of students in each set: - Students in any language class: 14 + 10 + 8 + 18 + 2 = 52 - Students not in any language class: 100 - 52 = 48
04

Calculate the probabilities

(a) The probability of a student not in any language class: P(not in any language class) = 48/100 = 0.48 (b) The probability of a student taking exactly one language class: P(exactly one language class) = (14 + 10 + 8)/100 = 32/100 = 0.32 (c) The probability of at least one student taking a language class if two are chosen randomly: We can find this by finding the complement of the probability that both students are not taking a language class. P(both not in any language class) = (48/100) * (47/99) = 0.230303 P(at least one in a language class) = 1 - P(both not in any language class) = 1 - 0.230303 = 0.769697. The resulting probabilities are: (a) P(not in any language class) = 0.48 (b) P(exactly one language class) = 0.32 (c) P(at least one in a language class) = 0.769697

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inclusion-Exclusion Principle
Understanding the Inclusion-Exclusion Principle is crucial for solving complex probability problems involving multiple events. This principle addresses situations where we must account for overlapping scenarios in order to avoid counting them multiple times. Imagine a Venn diagram where several circles (representing different events) overlap; some individuals may be part of more than one circle. The principle provides a way to accurately count individuals in any part of the diagram.

For example, in our textbook exercise with students enrolled in various language classes, we needed to count students taking exactly one, exactly two or all three classes, without mistakenly including someone twice or more. The Inclusion-Exclusion Principle uses the following formula for three sets A, B, and C:
\( |A \cup B \cup C| = |A| + |B| + |C| - |A \cap B| - |A \cap C| - |B \cap C| + |A \cap B \cap C| \)
This formula helped us find the number of students in any class and was pivotal in determining the probabilities of various selection scenarios.
Probabilistic Models
Probabilistic models provide a mathematical framework to study randomness and uncertainty. They are used to estimate the likelihood of different outcomes in a given situation. In these models, probabilities are assigned to outcomes in such a way that the total probability is 1, reflecting the certainty that one of the possible outcomes will occur.

In the classroom exercise, we used a probabilistic model to analyze the probability of students being in certain language classes. We began by establishing the sample space — all 100 students. Then, we determined the individual and combined probabilities of students being in different class sets. Finally, by applying these probabilities, we were able to determine the likelihood of selecting students enrolled in no language classes, exactly one class, or at least one class when picking at random. This model converts raw data into meaningful information that can guide decisions or predictions.
Combinatorial Probability
Combinatorial probability deals with counting and grouping. It helps us understand probabilities when dealing with discrete structures or finite sets, like counting the number of ways to arrange objects or the number of ways an event can occur. This branch of probability can be particularly useful when answering questions that require calculating the likelihood of various combinations of outcomes occurring.

In our textbook exercise related to language class enrollment, combinatorial probability techniques were required to answer part (c) of the problem. Here, we needed to calculate the likelihood of at least one out of two randomly chosen students being enrolled in a language class. This involved understanding combinations and the complementary probability, which in essence is another form of combinatorial reasoning. Understanding how to count and combine these probabilities is fundamental to solving any problem related to combinatorial probability.

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