91Ó°ÊÓ

Compute the probability that a bridge hand is void in at least one suit. Note that the answer is not $$ \frac{\left(\begin{array}{l} 4 \\ 1 \end{array}\right)\left(\begin{array}{l} 39 \\ 13 \end{array}\right)}{\left(\begin{array}{l} 52 \\ 13 \end{array}\right)} $$ (Why not?) Hint: Use Proposition 4.4.

Compute the probability that a hand of 13 cards contains (a) the ace and king of at least one suit; (b) all 4 of at least 1 of the 13 denominations.