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If \(X\) has distribution function \(F\), what is the distribution function of the random variable \(\alpha X+\beta\), where \(\alpha\) and \(\beta\) are constants, \(\alpha \neq 0\) ?

Short Answer

Expert verified
The distribution function \(G(y)\) of the random variable \(Y = \alpha X + \beta\) is given by: \[G(y) = F\left(\frac{y -\beta}{\alpha} \right)\] If we know the distribution function \(F(x)\) of the random variable \(X\), we can find the distribution function of \(Y\) by simply substituting \(\frac{y -\beta}{\alpha}\) into the original function.

Step by step solution

01

Define the New Distribution Function

Let the random variable \(Y = \alpha X + \beta\), and let its distribution function be denoted as \(G(y)\). The definition of \(G(y)\) should be given as: \[G(y) = P(Y \leq y) = P(\alpha X +\beta \leq y)\] The goal now is to express this probability in terms of the original distribution function \(F(x)\).
02

Express the New Distribution Function in Terms of the Original Distribution Function

Since we want to express \(G(y)\) in terms of \(F(x)\), we need to rewrite our equation in terms of \(X\). To do this, isolate \(X\) from the inequality: \[ P(\alpha X +\beta \leq y) \Rightarrow P \left(X \leq \frac{y -\beta}{\alpha} \right) \] Now we can express \(G(y)\) in terms of \(F(x)\): \[G(y) = P \left(X \leq \frac{y -\beta}{\alpha} \right) = F \left( \frac{y -\beta}{\alpha} \right)\]
03

Interpret the Result

The distribution function \(G(y)\) of the random variable \(Y=\alpha X + \beta\) is given by: \[G(y) = F\left(\frac{y -\beta}{\alpha} \right)\] This means that if we know the distribution function \(F(x)\) of the random variable \(X\), we can find the distribution function of \(Y\) by simply substituting \(\frac{y -\beta}{\alpha}\) into the original function. This result is useful when analyzing the behavior of transformed random variables and investigating how their probabilistic properties change under transformation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Random Variable Distribution Function
A random variable distribution function, typically denoted by \( F(x) \), describes the probability that a random variable \( X \) will take a value less than or equal to \( x \). This function is fundamental in understanding how probabilities are distributed over the set of possible values that \( X \) can assume.

Essential properties of distribution functions include:
  • The function \( F(x) \) is non-decreasing; that is, \( F(x_1) \leq F(x_2) \) for \( x_1 \leq x_2 \).
  • It ranges between 0 and 1, inclusive, with \( F(x) \to 1 \) as \( x \to \infty \) and \( F(x) \to 0 \) as \( x \to -\infty \).
  • The distribution function is right-continuous, meaning it does not change sharply at any point.
Understanding these basic features helps us in analyzing and predicting the behavior of random variables.

In practical terms, the distribution function can be used to assess the likelihood of various outcomes, such as determining percentile ranks in a data set. This forms the backbone of probabilistic analysis in fields ranging from finance to engineering.
Linear Transformation of Random Variables
A linear transformation of random variables involves altering a variable using a linear equation \( Y = \alpha X + \beta \), where \( \alpha \) and \( \beta \) are constants and \( \alpha eq 0 \). This type of transformation is common in statistics for standardizing test scores or in physics for scaling measurements.

Given that \( Y \) is a transformation of \( X \), if \( X \) is a random variable with a known distribution function \( F(x) \), our goal becomes finding the distribution function \( G(y) \) for \( Y \).

Such transformations maintain certain properties of the original distribution, such as linearity. Operations on the random variable through the transformation either stretch or compress the distribution based on \( \alpha \), and shift it based on \( \beta \).
Key things to remember include:
  • If \( \alpha > 0 \), the direction of inequality remains the same.
  • If \( \alpha < 0 \), the direction of inequality reverses.
This type of transformation enables us to adjust the scale and location of data without altering its inherent distribution shape, an essential feature in data normalization and regression analysis.
Distribution Function Analysis
Distribution function analysis involves examining how the probability distribution of a random variable alters when it undergoes transformations. By analyzing distribution functions, we can gain insights into the statistical properties of data and how they change under various operations.

In our exercise, distribution function analysis was applied to determine the effects of a linear transformation on a random variable's distribution function. The transformation \( Y = \alpha X + \beta \) changes the distribution of \( X \) to that of \( Y \). Here, the key is to express the distribution function of the transformed variable \( G(y) \) in terms of the original function \( F(x) \):

  • Isolating \( X \) in the inequality \( \alpha X + \beta \leq y \) allows us to write \( X \leq \frac{y - \beta}{\alpha} \).
  • This gives \( G(y) = F\left(\frac{y - \beta}{\alpha}\right) \), allowing any changes to \( Y \) to be directly derived from \( F(x) \).
This analytical approach enables us to understand how key probabilities distribute after the transformation, helping in real-world decisions such as pricing models in finance or risk assessments.

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Most popular questions from this chapter

A philanthropist writes a positive number \(x\) on a piece of red paper, shows it to an impartial observer, and then turns it face down on the table. The observer then flips a fair coin. If it shows heads, she writes the value \(2 x\), and, if tails, the value \(x / 2\), on a piece of blue paper which she then turns face down on the table. Without knowing either the value \(x\) or the result of the coin flip, you have the option of turning over either the red or the blue piece of paper. After doing so, and. observing the number written on that paper, you may elect to receive as a reward either that amount or the (unknown) amount written on the other piece of paper. For instance, if you elect to turn over the blue paper and observe the value 100 , then you can elect, either to accept 100 as your reward or to take the amount (either 200 or 50) on the red paper. Suppose that you would like your expected reward to be large. (a) Argue that there is no reason to turn over the red paper first because if you do so, then no matter what value you observe, it is always better to switch to the blue paper. (b) Let \(y\) be a fixed nonnegative value, and consider the following strategy. Tum over the blue paper and if its value is at least \(y\), then accept that amount. If it is less than \(y\), then switch to the red paper. Let \(R_{y}(x)\) denote the reward obtained if the philanthropist writes the amount \(x\) and you employ this strategy. Find \(E\left[R_{y}(x)\right]\). Note that \(E\left[R_{0}(x)\right]\) is the expected reward if the philanthropist writes the amount \(x\) when you employ the strategy of always choosing the blue paper.

A total of 4 buses carrying 148 students from the same school arrives at a football stadium. The buses carry, respectively, \(40,33,25\), and 50 students. One of the students is randomly selected. Let \(X\) denote the number of students that were on the bus carrying this randomly selected student. One of the 4 bus drivers is also randomly selected. Let \(Y\) denote the number of students on her bus. (a) Which of \(E[X]\) or \(E[Y]\) do you think is larger? Why? (b) Comnute \(F[X]\) and \(E[Y)\)

Let \(X\) represent the difference between the number of heads and the number of tails obtained when a coin is tossed \(n\) times. What are the possible values of \(X ?\)

Each of 500 soldiers in an army company independently has a certain disease with probability \(1 / 10^{3}\). This disease will show up in a blood test, and to facilitate matters blood samples from all 500 are pooled and tested. (a) What is the (approximate) probability that the blood test will be positive (and so at least one person has the disease)? Suppose now that the blood test yields a positive result. (b) What is the probability, under this circumstance, that more than one person has the disease? One of the 500 people is Jones, who knows that he has the disease. (c) What does Jones think is the probability that more than one person has the disease? As the pooled test was positive, the authorities have decided to test each individual separately. The first \(i-1\) of these tests were negative, and the ith one-which was on Jones-was positive. (d) Given the above, as a function of \(i\), what is the probability that any of the remaining people have the disease?

(a) An integer \(N\) is to be selected at random from \(\left\\{1,2, \ldots,(10)^{3}\right\\}\) in the sense that each integer has the same probability of being selected. What is the probability that \(N\) will be divisible by \(3 ?\) by \(5 ?\) by \(7 ?\) by \(15 ?\) by \(105 ?\) How would your answer change if \((10)^{3}\) is replaced by \((10)^{k}\) as \(k\) became larger and larger? (b) An important function in number theory - one whose properties can be shown to be related to what is probably the most important unsolved problem of mathematics, the Riemann hypothesis-is the Möbius function \(\mu(n)\), defined for all positive integral values \(n\) as follows: Factor \(n\) into its prime factors. If there is a repeated prime factor, as in \(12=\) \(2 \cdot 2 \cdot 3\) or \(49=7 \cdot 7\), then \(\mu(n)\) is defined to equal 0. Now let \(N\) be chosen at random from \(\left\\{1,2, \ldots(10)^{k}\right\\}\), where \(k\) is large. Determine \(P\\{\mu(N)=0\\}\) as \(k \rightarrow \infty\) HINT: To compute \(P\\{\mu(N) \neq 0\\}\), use the identity $$ \prod_{i=1}^{x} \frac{P_{i}^{2}-1}{P_{I}^{2}}=\left(\frac{3}{4}\right)\left(\frac{8}{9}\right)\left(\frac{24}{25}\right)\left(\frac{48}{49}\right) \cdots=\frac{6}{\pi^{2}} $$ where \(P_{i}\) is the \(i\) th smallest prime. (We do not include I as a prime.)

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