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Three prisoners are informed by their jailer that one of them has been chosen at random to be executed, and the other two are to be freed. Prisoner \(A\) asks the jailer to tell him privately which of his fellow prisoners will be set free, claiming that there would be no harm in divulging this information because he already knows that at least one of the two will go free. The jailer refuses to answer this question, pointing out that if \(A\) knew which of his fellow prisoners were to be set free, then his own probability of being executed would rise from \(\frac{1}{3}\) to \(\frac{1}{2}\) because he would then be one of two prisoners. What do you think of the jailer's reasoning?

Short Answer

Expert verified
The jailer's reasoning is correct. When information about the fellow prisoner set free is revealed to Prisoner A, his probability of being executed changes from \( \frac{1}{3}\) to \( \frac{1}{2}\). In both cases, whether B or C will be set free, A's probability of being executed becomes \( \frac{1}{2}\).

Step by step solution

01

Identify probabilities for each prisoner

Let's denote the prisoners as A, B, and C. Initially, each prisoner has equal chances of being executed, so the probability for each is: - Probability A being executed: \(P(A) = \frac{1}{3}\) - Probability B being executed: \(P(B) = \frac{1}{3}\) - Probability C being executed: \(P(C) = \frac{1}{3}\)
02

Assume that jailer would reveal the information

Now we assume that the jailer tells Prisoner A which of the two fellow prisoners (either B or C) will be set free. Let's explore both cases: Case 1: Jailor tells A that B will be set free. Then, these are the updated probabilities: - Probability A being executed: \(P(A| \neg B) = \frac{1}{2}\) (Since B is not executed) - Probability C being executed: \(P(C| \neg B) = \frac{1}{2}\) Case 2: Jailor tells A that C will be set free. Then, the new probabilities are: - Probability A being executed: \(P(A| \neg C) = \frac{1}{2}\) (Since C is not executed) - Probability B being executed: \(P(B| \neg C) = \frac{1}{2}\)
03

Compare the Jailor's reasoning

According to the jailer's reasoning, knowing the prisoner set free would increase Prisoner A's probability of being executed from 1/3 to 1/2. As observed in Step 2, when the information is revealed to A, his probability of being executed indeed changes to 1/2. In both cases (whether B or C will be set free), A's probability of being executed becomes 1/2. Therefore, the jailer's reasoning is correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conditional Probability
Conditional probability is a fundamental concept in probability theory that deals with determining the likelihood of an event, given that another event has already occurred. This is mathematically denoted by the notation \(P(A|B)\), which reads as 'the probability of event \(A\) given that event \(B\) has occurred'. The formal definition states that if the probability of event \(B\) is greater than zero, then the conditional probability of event \(A\), given \(B\), is given by:\[ P(A|B) = \frac{P(A \cap B)}{P(B)} \]In the context of our prisoner example, when Prisoner A asks the jailer about one of the others being set free, the probability of A's execution becomes conditioned on the information that another prisoner, say B, will not be executed. This can be misleading, as the conditional probability does not actually change the overall likelihood of A's execution from the initial state, which remains \(\frac{1}{3}\). In essence, the jailer's refusal to reveal information protects A from incorrectly assessing his odds of execution.
Probability Reasoning
Probability reasoning involves using logical analysis in conjunction with probabilistic concepts to form conclusions about uncertain events. It often requires careful consideration to avoid common fallacies and misinterpretations. In our prisoner problem, the intuitive reasoning might suggest that if Prisoner A knows one of his fellow prisoners will be set free, his odds of survival seem to increase. However, the actual mathematical reasoning demonstrates that such knowledge changes nothing about his own probability of execution, which is initially \(\frac{1}{3}\).

Misinterpretation vs. Mathematical Fact

Probability reasoning helps distinguish between what we may mistakenly perceive (misinterpretation) versus what the mathematics actually indicates (mathematical fact). While it may feel like A's chances of execution increase if one name is revealed, the mathematics clearly disagrees. Each prisoner's initial probability of execution remains unchanged by the conditional information — it requires a proper understanding of conditional probability to see why.
Bayes' Theorem
Bayes' theorem is a powerful tool in probability theory that allows us to update our beliefs or probabilities upon receiving new evidence. Named after the Reverend Thomas Bayes, this theorem relates the conditional and marginal probabilities of random events. The theorem can be written as:\[ P(A|B) = \frac{P(B|A)P(A)}{P(B)} \]Where:\(P(A)\) and \(P(B)\) are the probabilities of events A and B, \(P(B|A)\) is the probability of event B given event A, and \(P(A|B)\) is the probability of event A given event B. Bayes' theorem thus adjusts our initial beliefs (the prior probabilities) in the light of new evidence (the conditional probabilities).In the case of our three prisoners, we could use Bayes' theorem to update the probability of each prisoner's execution based on new information. However, in this scenario, the introduction of Bayes' theorem would not make much difference, as the initial probabilities are uniform and the condition itself doesn't provide new evidence about the likelihood of A's execution — it only alters A's perception. Understanding Bayes' theorem is essential for more complex problems where evidence significantly influences the outcome probabilities.

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