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What is the probability that at least one of a pair of fair dice lands on 6, given that the sum of the dice is \(i, i=2,3, \ldots, 12 ?\)

Short Answer

Expert verified
The probabilities of at least one die landing on 6, given the sums i from 2 to 12, are as follows: - i=2 : 0 - i=3 : 0 - i=4 : 0 - i=5 : 0 - i=6 : \( \frac{1}{4} \) - i=7 : \( \frac{1}{3} \) - i=8 : \( \frac{2}{5} \) - i=9 : \( \frac{1}{2} \) - i=10 : \( \frac{2}{3} \) - i=11 : 1 - i=12 : 0

Step by step solution

01

Case: i=2

This case is irrelevant because there is no situation where at least one die lands on 6 with the sum 2.
02

Case: i=3

There is only one combination to obtain the sum of 3: (1,2). No die has landed on 6. Therefore, the probability is 0.
03

Case: i=4

There are two combinations to obtain the sum of 4: (1,3) and (2,2). No die has landed on 6. Therefore, the probability is 0.
04

Case: i=5

There are three combinations to obtain the sum of 5: (1,4), (2,3), and (3,2). No die has landed on 6. Therefore, the probability is 0.
05

Case: i=6

There are four combinations to obtain the sum of 6: (1,5), (2,4), (3,3), and (4,2). Only one combination has at least one die landing on 6 (1,5). So, given that the sum is 6, the probability of at least one die landing on 6 is 1/4.
06

Case: i=7

There are five combinations to obtain the sum of 7: (1,6), (2,5), (3,4), (4,3), (5,2), and (6,1). Two combinations have at least one die landing on 6 (1,6) and (6,1). So, given that the sum is 7, the probability of at least one die landing on 6 is 2/6 = 1/3.
07

Case: i=8

There are four combinations to obtain the sum of 8: (2,6), (3,5), (4,4), (5,3), and (6,2). Two combinations have at least one die landing on 6 (2,6) and (6,2). So, given that the sum is 8, the probability of at least one die landing on 6 is 2/5.
08

Case: i=9

There are three combinations to obtain the sum of 9: (3,6), (4,5), (5,4), and (6,3). Two combinations have at least one die landing on 6 (3,6) and (6,3). So, given that the sum is 9, the probability of at least one die landing on 6 is 2/4 = 1/2.
09

Case: i=10

There are two combinations to obtain the sum of 10: (4,6), (5,5), and (6,4). Two combinations have at least one die landing on 6 (4,6) and (6,4). So, given that the sum is 10, the probability of at least one die landing on 6 is 2/3.
10

Case: i=11

There is only one combination to obtain the sum of 11: (5,6) and (6,5). Both combinations have at least one die landing on 6. So, given that the sum is 11, the probability of at least one die landing on 6 is 1.
11

Case: i=12

This case is irrelevant because there is no situation where at least one die lands on 6 with the sum 12. #Conclusion# Here are the probabilities of at least one die landing on 6, given the sums i from 2 to 12: - i=2 : 0 - i=3 : 0 - i=4 : 0 - i=5 : 0 - i=6 : 1/4 - i=7 : 1/3 - i=8 : 2/5 - i=9 : 1/2 - i=10 : 2/3 - i=11 : 1 - i=12 : 0

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fair Dice Probability
When we talk about a 'fair dice', we're describing a classic six-sided die where each face has an equal chance of landing face up on any given roll. In other words, the probability of rolling any number between 1 and 6 is exactly the same, and that probability is \(\frac{1}{6}\).As a fundamental concept in probability theory, it's crucial to understand that with a fair die, no outcome is favored over another. Each roll is independent, meaning that the outcome of one roll does not affect the outcome of the next. Given this, the likelihood of rolling a particular number like 6 on a single die is consistent across each roll.The independence of each roll becomes especially important when rolling multiple dice. The probabilities of different outcomes when two fair dice are rolled involve simple multiplications of individual outcomes since each die operates independently of the other.
Probability Given a Sum
Determining the probability when a sum is involved requires combinatorial logic. Let's consider two dice. The total number of possible outcomes when rolling two fair dice is \(\text{6} \times \text{6} = \text{36}\) because there are 6 outcomes for the first die and 6 for the second.

Conditional Probability

If we wish to find the probability of rolling a certain sum, such as 7, we need to consider all the ways we can achieve this sum. For example, (1,6), (2,5), (3,4), (4,3), (5,2), and (6,1). There are 6 combinations out of 36 possibilities, so the probability is \(\frac{6}{36} = \frac{1}{6}\).However, if we know that one die is already showing a particular number, this changes the sample space because not all 36 outcomes are possible anymore. We must then calculate the number of ways we can obtain the desired sum with this new information, re-evaluating the probability accordingly.
Combinatorics
Combinatorics is a branch of mathematics dealing with counting, both as a means and an end in obtaining results, and certain properties of finite structures. It plays a central role in the field of probability.When we calculate the probability of a certain event, we usually count the number of ways that event can occur and then compare it to the total number of possible outcomes. For instance, when looking at rolling dice, combinatorics tells us there are 36 different possible outcomes for the roll of two dice. We can use a grid or table to enumerate each possibility, which is a useful tool for visualizing and counting combinations.To improve understanding in this area, it’s helpful to practice listing all the possible outcomes for certain events and then identifying the part of the list that represents the event in question. Through practice, one becomes more adept at quickly assessing and calculating probabilities in a variety of situations using combinatorics.

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Most popular questions from this chapter

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