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91Ó°ÊÓ

Fifty-two percent of the students at a certain college are females. Five percent of the students in this college are majoring in computer science. Two percent of the students are women majoring in computer science. If a student is selected at random, find the conditional probability that (a) this student is female, given that the student is majoring in computer science; (b) this student is majoring in computer science, given that the student is female.

Short Answer

Expert verified
(a) The conditional probability that a student is female, given that the student is majoring in computer science, is \(0.4\) or \(40\%\). (b) The conditional probability that a student is majoring in computer science, given that the student is female, is approximately \(0.03846\) or \(3.846\%\).

Step by step solution

01

Find the probability of a female student given that they are majoring in Computer Science

We are given P(Female and Computer Science) = 0.02 and P(Computer Science) = 0.05. We can now use the conditional probability formula: P(Female | Computer Science) = P(Female and Computer Science) / P(Computer Science)
02

Calculate P(Female | Computer Science)

Inserting the given values in the equation we get: P(Female | Computer Science) = 0.02 / 0.05
03

Simplify the result

The result of the division is: P(Female | Computer Science) = 0.4 The probability that a student is female, given that they are majoring in computer science, is 0.4 or 40%.
04

Find the probability of a student majoring in Computer Science given that they are female

We are given P(Female and Computer Science) = 0.02 and P(Female) = 0.52. We can now use the conditional probability formula: P(Computer Science | Female) = P(Female and Computer Science) / P(Female)
05

Calculate P(Computer Science | Female)

Inserting the given values into the equation we get: P(Computer Science | Female) = 0.02 / 0.52
06

Simplify the result

The result of the division is: P(Computer Science | Female) ≈ 0.03846 The probability that a student is majoring in computer science, given that the student is female, is approximately 0.03846 or 3.846%. So, the answers to the exercise are: (a) The probability that a student is female, given that the student is majoring in computer science, is 0.4 or 40%. (b) The probability that a student is majoring in computer science, given that the student is female, is approximately 0.03846 or 3.846%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Theory
Probability theory is a branch of mathematics concerned with the analysis of random phenomena. The central objects of probability theory are random variables, events, and processes. This theory is foundational for understanding chance and uncertainty, and it is applicable in many fields, including science, engineering, economics, and, importantly, education.
Bayes' Theorem
Bayes' theorem is a formula that describes how to update the probabilities of hypotheses when given evidence. It's named after Thomas Bayes, who first provided an equation that allows new evidence to update beliefs. The theorem is written as:

\[ P(A|B) = \frac{P(B|A) \cdot P(A)}{P(B)} \]

where \( P(A|B) \) is the probability of hypothesis \( A \) given the evidence \( B \), \( P(B|A) \) is the probability of evidence \( B \) given that hypothesis \( A \) is true, \( P(A) \) is the probability of hypothesis \( A \), and \( P(B) \) is the probability of the evidence. This theorem is invaluable not only in probability and statistics but also in various fields, including medical diagnosis, spam filtering, and even legal reasoning.
Statistics in Education
Statistics plays a vital role in education, providing tools for designing experiments, studying data, making predictions, and informing decisions. Educators and policymakers alike rely on statistical analyses to assess student performance, evaluate the effectiveness of instructional methods, and to make data-driven decisions to enhance the educational process. Statistics also help in identifying trends and educational needs which can influence curriculum development, resource allocation, and policy reforms.
Probability Exercises
Probability exercises are practical tools for students to apply their understanding of probability theories and for teachers to assess their students' grasp of the concept. These exercises range from simple problems that test basic understanding to more complex scenarios that require nuanced thinking and the application of advanced principles, like conditional probability and Bayes' theorem. Effective probability exercises should build a student's intuition for statistical thinking and the stochastic nature of the world around us.

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Most popular questions from this chapter

A ball is in any one of \(n\) boxes. It is in the \(i\) th box with probability \(P_{i}\). If the ball is in box \(i\), a search of that box will uncover it with probability \(\alpha_{i}\). Show that the conditional probability that the ball is in box \(j\), given that a search of box \(i\) did not uncover it, is $$ \begin{array}{cl} \frac{P_{j}}{1-\alpha_{i} P_{i}} & \text { if } j \neq i \\ \frac{\left(1-\alpha_{i}\right) P_{i}}{1-\alpha_{i} P_{i}} & \text { if } j=i \end{array} $$

An event \(F\) is said to carry negative information about an event \(E\), and we write \(F \searrow E\) if $$ P(E \mid F) \leq P(E) $$ Prove or give counterexamples to the following assertions: (a) If \(F \searrow E\), then \(E \searrow F\). (b) If \(F \searrow E\) and \(E \searrow G\), then \(F \searrow G\). (c) If \(F \searrow E\) and \(G \searrow E\), then \(F G \searrow E\). Repeat parts (a), (b), and (c) when \(\searrow\) is replaced by \(\lambda\), where we say that \(F\) carries positive information about \(E\), written \(F \nearrow E\), when \(P(E \mid F) \geq P(E)\)

Consider the gambler's ruin problem with the exception that \(A\) and \(B\) agree to play no more than \(n\) games. Let \(P_{n, i}\) denote the probability that \(A\) winds up with all the money when \(A\) starts with \(i\) and \(B\) with \(N-i\). Derive an equation for \(P_{n, i}\) in terms of \(P_{n-1, i+1}\) and \(P_{n-1, i-1}\) and compute \(P_{7,3}\), \(N=5\)

Suppose that there was a cancer diagnostic test that was 95 percent accurate both on those that do and those that do not have the disease. If \(.4\) percent of the population have cancer, compute the probability that a tested person has cancer, given that his or her test result indicates so.

There are 3 coins in a box. One is a two-headed coin; another is a fair coin; and the third is a biased coin that comes up heads 75 percent of the time. When one of the 3 coins is selected at random and flipped, it shows heads. What is the probability that it was the two-headed coin?

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