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Consider two boxes, one containing 1 black and 1 white marble, the other 2 black and 1 white marble. A box is selected at random, and a marble is drawn at random from the selected box. What is the probability that the marble is black? What is the probability that the first box was the one selected, given that the marble is white?

Short Answer

Expert verified
The probability that the marble drawn is black is \( \frac{7}{12} \). The probability that the first box was the one selected, given that the marble drawn is white, is \( \frac{3}{10} \).

Step by step solution

01

Define events

Let the following events be defined: - A1: Box 1 is selected - A2: Box 2 is selected - B: The black marble is drawn - W: The white marble is drawn Since we are selecting either Box 1 or Box 2, we can say: P(A1) = 1/2 and P(A2) = 1/2.
02

Calculate probabilities for black marbles

We need to find the probability of drawing a black marble (B) from each box. From Box 1 (one black and one white marble): P(B | A1) = 1/2 From Box 2 (two black and one white marble): P(B | A2) = 2/3 Now we can find the probability that the marble drawn is black by using the law of total probability: P(B) = P(B | A1) * P(A1) + P(B | A2) * P(A2)
03

Calculate the probability that the marble drawn is black

Now replace the values we found: P(B) = (1/2) * (1/2) + (2/3) * (1/2) = (1/4) + (1/3) = 7/12 So, the probability that the marble drawn is black is 7/12.
04

Calculate probabilities for white marbles

We need to find the probability of drawing a white marble (W) from each box. From Box 1 (one black and one white marble): P(W | A1) = 1/2 From Box 2 (two black and one white marble): P(W | A2) = 1/3
05

Use Bayes' theorem to find the probability that the first box was the one selected, given that the marble drawn is white

We want to find P(A1 | W). Using Bayes' theorem, we have: P(A1 | W) = P(W | A1) * P(A1) / P(W) Since we have already calculated P(W | A1) and P(A1), we only need to find P(W) using the law of total probability: P(W) = P(W | A1) * P(A1) + P(W | A2) * P(A2) Substituting the values: P(W) = (1/2) * (1/2) + (1/3) * (1/2) = (1/4) + (1/6) = 5/12 Now, replace the known values in Bayes' theorem: P(A1 | W) = (1/2) * (1/2) / (5/12) = (1/4) / (5/12) = (3/10) So, the probability that the first box was the one selected, given that the marble drawn is white, is 3/10.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bayes' Theorem
Bayes' theorem is a way to reverse conditional probabilities. It allows us to update our beliefs based on new evidence. Let's take a real-world example: imagine you're at a friend's house playing a game where you draw marbles from a box without looking. If you draw a white marble, you might wonder which box you drew it from. This is where Bayes' theorem shines.

In mathematical terms, it’s expressed as: \[ P(A|B) = \frac{P(B|A) \times P(A)}{P(B)} \] where:
  • \(P(A|B)\) is the probability that event \(A\) occurs given \(B\) is true.
  • \(P(B|A)\) is the probability that event \(B\) occurs given \(A\) is true.
  • \(P(A)\) is the probability of event \(A\) occurring on its own.
  • \(P(B)\) is the probability of event \(B\) occurring on its own.

By applying Bayes' theorem, we can find out how likely it is that a particular box was chosen based on the color of the marble we've drawn. This is exactly what we did in the marble example from the exercise. Bayes' theorem allows us to update our probability assessment for selecting Box 1 once we know a white marble has been drawn, shifting our understanding from a general idea to a more specific one.
Law of Total Probability
The law of total probability is essential when dealing with complex problems that involve multiple scenarios or stages. It helps us break down probabilities into more manageable parts.

In essence, the law of total probability states that if we have a set of mutually exclusive events, the total probability of another event \(B\) can be found by summing the probability of \(B\) occurring within each of the exclusive events.

Mathematically, it looks like this for events \(A1\), \(A2\), ..., \(An\):\[ P(B) = P(B|A1)P(A1) + P(B|A2)P(A2) + ... + P(B|An)P(An) \]In the marble-drawing problem, we have two mutually exclusive events – selecting Box 1 or Box 2. Using the law of total probability, we combined the chances of drawing a black marble from both boxes to get the overall probability for drawing a black marble, irrespective of the box. It's like summing up the chances of rain from multiple weather forecasts to get a more complete picture of whether you'll need an umbrella today.
Conditional Probability
Conditional probability is the chance of an event occurring given that another event has already occurred. It's a bit like betting on the outcome of a football match at halftime—you have more information than before the game started, and that changes the odds.

The formula for conditional probability is: \[ P(A|B) = \frac{P(A \cap B)}{P(B)} \] where:
  • \(P(A|B)\) is the probability of \(A\) given \(B\) has occurred.
  • \(P(A \cap B)\) is the joint probability that both \(A\) and \(B\) occur.
  • \(P(B)\) is the probability that \(B\) occurs.

In our marble example, the conditional probability tells us the likelihood of drawing a black marble given that we've chosen a specific box. This helps us to be more precise in our predictions. Remembering that probabilities are just a way of expressing our uncertainty about events, conditional probability gives us a tool to refine that uncertainty when we gain more information about what has happened.

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