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What is the relationship Pressure and temperature for an ideal gas undergoing adiabatic Change. (A) \(\mathrm{PT}^{\gamma}=\) Const (B) \(\mathrm{PT}^{-1+\gamma}=\) Const (C) \(\mathrm{P}^{1-\gamma} \mathrm{T}^{\gamma}=\) Const (D) \(\mathrm{P}^{\gamma-1} \mathrm{~T}^{\gamma}=\) Const

Short Answer

Expert verified
The relationship between Pressure and temperature for an ideal gas undergoing adiabatic change is given by: \(\mathrm{P}^{1-\gamma} \mathrm{T}^{\gamma} = \text{Const}\) (Option C).

Step by step solution

01

Remember the adiabatic equation for an ideal gas

The adiabatic equation for an ideal gas is \(PV^{\gamma} = \text{constant}\), where P is pressure, V is volume, \(\gamma\) (gamma) is the specific heat ratio or adiabatic index (\(\frac{C_p}{C_v}\)), and \(PV^{\gamma}\) is constant during the adiabatic process.
02

Eliminate volume (V) term from adiabatic equation

To eliminate the volume (V) term, we can use the ideal gas equation, \(PV=nRT\), where n is the number of moles of the gas and R is the universal gas constant. Divide both sides by P: \(V = \frac{nRT}{P}\) Now substitute this expression for V in the adiabatic equation: \(P\left(\frac{nRT}{P}\right)^{\gamma} = \text{constant}\)
03

Simplify the equation

Distribute the \(\gamma\) exponent: \(P\left(\frac{n^{\gamma}R^{\gamma}T^{\gamma}}{P^{\gamma}}\right) = \text{constant}\) Simplify the equation by multiplying P: \(P^{1-\gamma}T^{\gamma} = \frac{n^{\gamma}R^{\gamma}}{\text{constant}}\) Since we need to find the relationship between P and T, both sides of the equation are constants, so it can be expressed as: \(P^{1-\gamma}T^{\gamma} = \text{constant}\)
04

Compare with given options

Based on our derived relationship between pressure and temperature for an ideal gas undergoing adiabatic change, the correct option is: (C) \(\mathrm{P}^{1-\gamma} \mathrm{T}^{\gamma} = \text{Const}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ideal Gas Law
The ideal gas law is a fundamental relation between key properties of an ideal gas. It is expressed by the equation \(PV = nRT\). This means that the product of pressure (P) and volume (V) of a gas equals the number of moles (n) times the universal gas constant (R) times the temperature (T).
- **Pressure (P):** The force that the gas exerts on the walls of its container.- **Volume (V):** The amount of space that the gas occupies.- **Temperature (T):** A measure of the average kinetic energy of gas particles.- **Moles (n):** The amount of substance of the gas.- **Universal Gas Constant (R):** A constant value that makes the equation valid across different gases and conditions.
This equation helps us understand how these properties change in relation to each other. For example, if you increase the temperature of a gas while keeping the volume constant, the pressure will increase.
Specific Heat Ratio
The specific heat ratio, often symbolized as \( \gamma \) (gamma), is the ratio of the specific heat at constant pressure \( (C_p) \) to the specific heat at constant volume \( (C_v) \). It is a crucial parameter in thermodynamics when studying gases.
- **\(C_p\):** The amount of energy required to raise the temperature of a unit mass of gas by one degree with constant pressure.- **\(C_v\):** The amount of energy needed to raise the temperature of a unit mass of gas by one degree with constant volume.- **Specific Heat Ratio (\( \gamma \)):** Defined as \( \gamma = \frac{C_p}{C_v} \).
For an ideal gas, \( \gamma \) is a measure of how the energy is distributed between pressure and volume changes. This ratio is important in adiabatic processes, where we deal with energy changes without heat exchange. It affects how much the temperature changes for a given pressure or volume change.
Pressure-Temperature Relationship
In an adiabatic process, the relationship between pressure and temperature can be derived from combining the ideal gas law and adiabatic conditions. Unlike an isothermal process where temperature remains constant, an adiabatic process involves changes in temperature.
Given the adiabatic equation \(PV^{\gamma} = \text{constant}\), along with the ideal gas equation \(PV = nRT\), we understand that eliminating volume leads to a pressure-temperature relationship.
When simplifying, you arrive at the equation \(P^{1-\gamma}T^{\gamma} = \text{constant}\). This shows how pressure and temperature interdependently vary without a change in the total heat content of the system.
Understanding this relationship helps in predicting how a gas's pressure will change if the temperature varies during quick compressions or expansions, often seen in engines and atmospheric phenomena.
Adiabatic Equation
An adiabatic equation for an ideal gas describes the relationship during an adiabatic process, which means no heat is transferred into or out of the system. This can occur in processes that are very fast, where there is no time for heat transfer.
The standard adiabatic equation is given by \(PV^{\gamma} = \text{constant}\), where \(P\) is pressure, \(V\) is volume, and \(\gamma\) is the specific heat ratio. However, when focusing on the pressure-temperature relationship, without considering the volume, the equation is expressed as \(P^{1-\gamma}T^{\gamma} = \text{constant}\).
This form shows the connection between pressure and temperature in an adiabatic process. It implies that if pressure increases, temperature must also increase to keep the equation constant, assuming other variables don't change.
Such an equation is pivotal in understanding the behavior of gases in engines, weather systems, and other rapid changes where no heat is exchanged.

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Most popular questions from this chapter

One mole of oxygen is heated at constant pressure starting at \(0^{\circ} \mathrm{C}\). How much heat energy in cal must be added to the gas to double its volume ? Take \(\mathrm{R}=2\\{(\mathrm{cal}) /(\) mole \()\\}\) (A) 1938 (B) 1920 (C) 1911 (D) 1957

If the ratio of specific heat of a gas at Constant pressure to that at constant volume is \(\gamma\), the Change in internal energy of the mass of gas, when the volume changes from \(\mathrm{V}\) to \(2 \mathrm{~V}\) at Constant Pressure p, is (A) \(\\{(\mathrm{PV}) /(\gamma-1)\\}\) (B) \(\\{\mathrm{R} /(\gamma-1)\\}\) (C) PV (D) \(\\{(\gamma \mathrm{PV}) /(\gamma-1)\\}\)

Instructions:Read the assertion and reason carefully to mask the correct option out of the options given below. (A) If both assertion and reason are true and the reason is the correct explanation of the assertion. (B) If both assertion and reason are true but reason is not be correct explanation of assertion. (C) If assertion is true but reason is false. (D) If the assertion and reason both are false. Assertion: The total translation kinetic energy of all the molecules of a given mass of an ideal gas is \(1.5\) times the product of its Pressure and its volume. Reason: The molecules of a gas collide with each other and velocities of the molecules change due to the collision (A) D (B) \(\mathrm{C}\) (C) A (D) B

A diatomic gas initially at \(18^{\circ} \mathrm{C}\) is Compressed adiabatically to one eighth of its original volume. The temperature after Compression will be (A) \(10^{\circ} \mathrm{C}\) (B) \(668 \mathrm{~K}\) (C) \(887^{\circ} \mathrm{C}\) (D) \(144^{\circ} \mathrm{C}\)

One mole of an ideal gas \(\left(\mathrm{C}_{\mathrm{p}} / \mathrm{C}_{\mathrm{v}}\right)=\gamma\) at absolute temperature \(\mathrm{T}_{1}\) is adiabatically compressed from an initial pressure \(\mathrm{P}_{1}\) to a final pressure \(\mathrm{P}_{2}\) The resulting temperature \(\mathrm{T}_{2}\) of the gas is given by. (A) \(\mathrm{T}_{2}=\mathrm{T}_{1}\left\\{\mathrm{p}_{2} / \mathrm{p}_{1}\right\\}^{\\{\gamma /(\gamma-1)\\}}\) (B) \(\mathrm{T}_{2}=\mathrm{T}_{1}\left\\{\mathrm{p}_{2} / \mathrm{p}_{1}\right\\}^{\\{(\gamma-1) / \gamma\\}}\) (C) \(\mathrm{T}_{2}=\mathrm{T}_{1}\left\\{\mathrm{p}_{2} / \mathrm{p}_{1}\right\\}^{\gamma}\) (D) \(\mathrm{T}_{2}=\mathrm{T}_{1}\left(\mathrm{p}_{2} / \mathrm{p}_{1}\right)^{\gamma-1}\)

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