/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Free solutions & answers for JEE Physics Chapter 22 - (Page 1) [step by step] | 91Ó°ÊÓ

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Problem 2775

When the screw and stud touch each other, the edges of a certain screw gauge is on left of the \(\mathrm{O}\) mark on the main scale and the \(96^{\text {th }}\) division of the circular scale coincides with the circular line of graduation then what is the value of zero error? (A) zero error \(=+0.96 \mathrm{~mm}\) (B) zero error \(=-0.96 \mathrm{~mm}\) (C) zero error \(=+0.04 \mathrm{~mm}\) (D) zero error \(=-0.04 \mathrm{~mm}\)

Problem 2777

Screw gauge A has a pitch of \(1 \mathrm{~mm}\) and 50 divis1on on its circular scale screw gauge \(B\) has a pitch of \(0.5 \mathrm{~mm}\) and 100 divisions on its circular scale. If \((\mathrm{L} \times \mathrm{C})\) is least count, then which posibility is true ? What is the parilrility? (A) \(2(\mathrm{~L} \times \mathrm{C})_{\mathrm{A}}=(\mathrm{L} \times \mathrm{C})_{\mathrm{B}}\) (B) \((\mathrm{L} \times \mathrm{C})_{\mathrm{A}}=4(\mathrm{~L} \times \mathrm{C})_{\mathrm{B}}\) (C) \((\mathrm{L} \times \mathrm{C})_{\mathrm{A}}=(\mathrm{L} \times \mathrm{C})_{\mathrm{B}}\) (D) \((\mathrm{L} \times \mathrm{C})_{\mathrm{A}}=2(\mathrm{~L} \times \mathrm{C})_{\mathrm{B}}\)

Problem 2779

The pitch of screw gauge is \(1 \mathrm{~mm}\) and there are 100 divisions on the circular scale. What measuring the diameter of a wire, the linear scale reads, \(1 \mathrm{~mm}\) and \(47^{\text {th }}\) division on the circular scale coincides with the reference line. The length of the wire is \(5.6 \mathrm{~cm}\). What will be the curved surface area (in \(\mathrm{cm}^{2}\) ) of the wire in appropriate number of significant figures. (A) \(2.6 \mathrm{~cm}^{2}\) (B) \(2.5848 \mathrm{~cm}^{2}\) (C) \(2.585 \mathrm{~cm}^{2}\) (D) \(2.5 \mathrm{~cm}^{2}\)

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