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The temperature of a wire of length 1 meter and area of cross-sectional section \(1 \mathrm{~cm}^{2}\) is increased from \(0^{\circ}\) to \(100^{\circ} \mathrm{C}\). If the rod is not allowed to increase in length. What will be the force required ? \(\left[\alpha=10^{-5} /{ }^{\circ} \mathrm{C}, \mathrm{Y}=10^{11}\left(\mathrm{~N} / \mathrm{m}^{2}\right)\right]\) (A) \(10^{3} \mathrm{~N}\) (B) \(10^{4} \mathrm{~N}\) (C) \(10^{5} \mathrm{~N}\) (D) \(10^{9} \mathrm{~N}\)

Short Answer

Expert verified
The force required to prevent the wire from expanding is \(10^{4} N\). So, the correct answer is (B).

Step by step solution

01

1. Convert area to the proper unit

Since the given area is in cm虏, we need to convert it to m虏: Area = 1 cm虏 = 0.0001 m虏
02

2. Calculate the change in length of the wire

Using the linear expansion formula, we can calculate the change in length: 螖L = 伪 * L * 螖T Where: 伪 = 10鈦烩伒 /掳C (coefficient of linear expansion) L = 1 m (initial length of the wire) 螖T = 100 掳C (change in temperature) 螖L = (10鈦烩伒 /掳C)(1 m)(100 掳C) = 0.001 m
03

3. Calculate the extension (strain) of the wire

Strain is the ratio of the change in length to the original length: Strain = 螖L / L Strain = 0.001 m / 1 m = 0.001
04

4. Use Young's modulus to find the stress

Now we can use the formula for Young's modulus: Y = stress / strain Where Y is the Young's modulus and is given as 10鹿鹿 N/m虏. We can rearrange the formula to find the stress: Stress = Y * strain Stress = (10鹿鹿 N/m虏)(0.001) = 10鈦 N/m虏
05

5. Find the force required to prevent the wire from expanding

Now we have the stress, we can find the force using the formula: Force = Stress * Area Force = (10鈦 N/m虏)(0.0001 m虏) = 10鈦 N The force required to prevent the wire from expanding is 10鈦 N. So, the correct answer is (B).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Expansion
When materials are subjected to temperature changes, they tend to change in size. In physics, this phenomenon is known as thermal expansion, and the linear expansion specifically refers to the change in length of an object. The formula used to calculate the change in length due to thermal expansion is:
  • \( \Delta L = \alpha \times L \times \Delta T \)
Where:
  • \( \Delta L \) is the change in length.
  • \( \alpha \) is the coefficient of linear expansion.
  • \( L \) is the original length of the object.
  • \( \Delta T \) is the change in temperature.
In the exercise, the wire initially has a length of 1 meter. It is subjected to a temperature increase from \( 0^{\circ} \mathrm{C} \) to \( 100^{\circ} \mathrm{C} \). Utilizing the linear expansion coefficient \( \alpha = 10^{-5} / \degree \mathrm{C} \), we can calculate that the length would increase by 0.001 meters if allowed.
Young's Modulus
Young's modulus is a measure of the stiffness of a material. It is a mechanical property that describes the material's ability to withstand changes in length when under tension or compression. Mathematically, Young's modulus \( Y \) is defined as the ratio of tensile stress \( \sigma \) to tensile strain \( \epsilon \):
  • \( Y = \frac{\text{Stress}}{\text{Strain}} \)
Where:
  • Stress \( \sigma = \frac{F}{A} \) (force per unit area)
  • Strain \( \epsilon = \frac{\Delta L}{L} \) (change in length per unit length)
The Young's modulus for steel, as given in the problem, is \( 10^{11} \text{ N/m}^2 \). This value indicates that steel is a very stiff material. In the context of the exercise, we used Young's modulus to derive the stress experienced by the material due to the constraint against thermal expansion.
Thermal Stress
Thermal stress arises when a material is prevented from expanding or contracting with changes in temperature. If a wire is heated, it naturally wants to expand, but if it is constrained, stress develops within the material. The thermal stress \( \sigma_t \) can be calculated using the relation from Young's modulus and strain:
  • \( \sigma_t = Y \times \epsilon \)
From the exercise:
  • Strain \( \epsilon \) was found to be 0.001
  • Young's modulus \( Y \) is \( 10^{11} \text{ N/m}^2 \)
Therefore, the stress induced in the wire owing to the restriction of length change is \( 10^8 \text{ N/m}^2 \). This stress measures the internal force per unit area resisting the thermal expansion.
Strain and Stress
Strain and stress are fundamental concepts in understanding material behavior under loads. **Strain** \( \epsilon \), is a dimensionless number representing the deformation of a material. It is the ratio of the change in dimension (length, area, or volume) to the original dimension of the object involved:
  • \( \epsilon = \frac{\Delta L}{L} \)
**Stress** \( \sigma \), on the other hand, is the force exerted per unit area within materials. It results from externally applied forces, uneven heating, or permanent deformation, and is given by:
  • \( \sigma = \frac{F}{A} \)
In the exercise, stress was used to determine the force necessary to prevent the wire鈥檚 expansion, which was effectively calculated by multiplying the stress \( 10^8 \text{ N/m}^2 \) with the area of cross-section \( 0.0001 \text{ m}^2 \), yielding a force of \( 10^4 \text{ N} \). This demonstrates the interplay between stress, strain, and material response to prevent deformation.

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Most popular questions from this chapter

Read the assertion and reason carefully to mark the correct option out of the option given below. (a) If both assertion and reason are true and the reason is the correct explanation of the reason. (b) If both assertion and reason are true but reason is not the correct explanation of the assertion. (c) If assertion is true but reason is false. (d) If the assertion and reason both are false. (e) If assertion is false but reason is true. Assertion: Fahrenheit is the smallest unit measuring temperature. Reason: Fahrenheit was the first temperature scale used for measuring temperature. (A) \(a\) (B) b (C) \(c\) (D) d (E) e

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When \(100 \mathrm{~N}\) tensile force is applied to a rod of \(10^{-6} \mathrm{~m}^{2}\) cross-sectional area, its length increases by \(1 \%\) so young's modulus of material is \(\ldots \ldots \ldots \ldots\) (A) \(10^{12} \mathrm{~Pa}\) (B) \(10^{11} \mathrm{~Pa}\) (C) \(10^{10} \mathrm{~Pa}\) (D) \(10^{2} \mathrm{~Pa}\)

Two wires \(A \& \mathrm{~B}\) of same length and of the same material have the respective radius \(\mathrm{r}_{1} \& \mathrm{r}_{2}\) their one end is fixed with a rigid support and at the other end equal twisting couple is applied. Then what will we be the ratio of the angle of twist at the end of \(\mathrm{A}\) and the angle of twist at the end of \(\mathrm{B}\). (A) \(\left(\mathrm{r}_{1}^{2} / \mathrm{r}_{2}^{2}\right)\) (B) \(\left(\mathrm{r}_{2}^{2} / \mathrm{r}_{1}^{2}\right)\) (C) \(\left(\mathrm{r}_{2}^{4} / \mathrm{r}_{1}^{4}\right)\) (D) \(\left(\mathrm{r}_{1}^{4} / \mathrm{r}_{2}^{4}\right)\)

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