Chapter 36: Problem 2891
A light ray is incident perpendicular to one face of \(90^{\circ}\) prism and is totally internally reflected at the glass-air interface. If the angle of reflection is \(45^{\circ} .\) We conclude that the refractive index \(\ldots\) (A) \(\mu>\sqrt{2}\) (B) \(\mu>(1 / \sqrt{2})\) (C) \(\mu<\sqrt{2}\) (D) \(\mu<(1 / \sqrt{2})\)
Short Answer
Step by step solution
Draw the Prism
Identify the Perpendicular Angle
Use Snell's Law on the Incident Ray
Input the Known Values and Solve for r
Apply Amici's Law
Find d using the Refraction Angle
Apply the Critical Angle Formula
Apply Total Internal Reflection Condition
Identify the Condition for Refractive Index
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Critical Angle
- When light hits at the critical angle, it refracts at 90° along the boundary.
- If the angle of incidence surpasses the critical angle, total internal reflection keeps the light inside the first medium.
Snell's Law
- \( \mu_1 \) and \( \mu_2 \) are the refractive indices of the two media.
- \( i \) is the angle of incidence.
- \( r \) is the angle of refraction.
Refractive Index
- \( c \) is the speed of light in a vacuum.
- \( v \) is the speed of light in the medium.
Prism
- Prisms often have a triangular shape and are characterized by their angles, like the 90° angle in the exercise.
- Light entering perpendicular to one face travels without deviation until it encounters another surface at an adequate angle for total internal reflection.