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If \(\propto\) -particle and proton have same velocities, the ratio of de Broglie wavelength of \(\propto\) -particle and proton is \(\ldots \ldots\) (A) \((1 / 4)\) (B) \((1 / 2)\) (C) 1 (D) 2

Short Answer

Expert verified
The ratio of de Broglie wavelength of 饾浖-particle and proton when they have the same velocities is \(\frac{1}{4}\).

Step by step solution

01

Find the de Broglie wavelength formula

The de Broglie wavelength formula states that the wavelength (位) is related to the momentum (p) of a particle using Planck鈥檚 constant (h) as follows: \[位 = \frac{h}{p}\]
02

Express momentum in terms of mass and velocity

We know that the momentum (p) can be expressed as the product of the mass (m) and velocity (v) of a particle: \[p = m \cdot v\]
03

Substitute momentum expression into de Broglie wavelength formula

Using our expression for momentum, we can rewrite the de Broglie wavelength formula as follows: \[位 = \frac{h}{m \cdot v}\]
04

Set up the ratio for the wavelengths of 饾浖-particle and proton

Let 位_伪 and 位_p be the de Broglie wavelengths of the 饾浖-particle and proton, respectively. We can set up a ratio as follows: \[\frac{位_伪}{位_p} = \frac{\frac{h}{m_伪 \cdot v}}{\frac{h}{m_p \cdot v}}\]
05

Simplify the ratio

Since the 饾浖-particle and proton have the same velocity, we can simplify the ratio by canceling out the "h" and "v" terms and solving for the mass ratio: \[\frac{位_伪}{位_p} = \frac{m_p}{m_伪} \]
06

Use given masses for 饾浖-particle and proton to find the ratio

Given that the mass of 饾浖-particle (m_伪) is 4 times the mass of a proton (m_p), we can substitute this information into the ratio formula: \[\frac{位_伪}{位_p} = \frac{m_p}{4 \cdot m_p}\]
07

Calculate the final ratio

By canceling out m_p, we are left with the final ratio of the de Broglie wavelengths of 饾浖-particle and proton: \[\frac{位_伪}{位_p} = \frac{1}{4}\] Thus, the correct answer is: (A) \((\frac{1}{4})\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Momentum
Momentum is a fundamental concept in physics. It's often described as the "quantity of motion" an object has. It depends on two factors:
  • Mass: Larger objects have more momentum.
  • Velocity: Faster objects also have more momentum.
Mathematically, momentum (denoted as "p") is found by the formula: \[ p = m \cdot v \] Where:
  • \( m \) is the mass of the object.
  • \( v \) is the velocity of the object.
Hence, if either the mass or the velocity increases, the momentum will increase too. Understanding momentum is crucial for solving various physics problems, including those involving de Broglie wavelengths.
Planck鈥檚 Constant
Planck鈥檚 constant is a pivotal part of quantum mechanics. It is a tiny number with a symbol \( h \) and a value of approximately \( 6.626 \times 10^{-34} \) m虏 kg / s.
Planck's constant is used to relate the energy of a particle to its frequency. In connection with de Broglie wavelength, it helps to determine the wavelength associated with the momentum of a particle. The de Broglie equation given by: \[ \lambda = \frac{h}{p} \] unites Planck's constant with the particle's momentum \( p \) to find the wavelength \( \lambda \).
This means that smaller particles like electrons have significant wavelengths and wave-like behaviors, while macroscopic objects, like baseballs, have wavelengths that are practically undetectable.
Alpha Particle
Alpha particles are a type of ionizing radiation ejected by certain radioactive decay processes. They are composed of:
  • 2 protons
  • 2 neutrons
This composition makes alpha particles the same as helium nuclei. They are relatively massive compared to other particles, which affects their momentum and hence their de Broglie wavelength.
Due to their larger mass, when alpha particles travel at the same velocity as smaller particles, such as protons or electrons, their de Broglie wavelength will be much shorter because the momentum \( (m \cdot v) \) is larger.
Understanding alpha particles is key when dealing with nuclear physics and radiation, providing insights into the behavior of matter at the atomic and subatomic levels.
Proton
Protons are one of the fundamental particles that make up matter. They are found in the nucleus of an atom and have:
  • a positive charge
  • a mass of approximately \( 1.67 \times 10^{-27} \) kg
Because protons are much less massive than alpha particles, they exhibit longer de Broglie wavelengths at the same velocity. This property becomes important in particle physics and quantum mechanics.
In the scenario where protons and alpha particles have the same velocity, as outlined in the exercise solution, the smaller mass of protons means their momentum is less than that of alpha particles.
This results in a longer de Broglie wavelength for protons, highlighting the influence that mass and velocity have on the wave-particle duality that is central to quantum mechanics.

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Most popular questions from this chapter

The de-Broglie wavelength of a proton and \(\alpha\) - particle is same. The ratio of their velocities will be.......... ( \(\alpha\) particle is the He- nucleus, having two protons and two neutrons. Thus, its mass \(\mathrm{M}_{\alpha}=4 \mathrm{~m}_{\mathrm{p}}\) where \(\mathrm{m}_{\mathrm{p}}\) is the mass of the proton.) (A) \(1: 4\) (B) \(1: 2\) (C) \(2: 1\) (D) \(4: 1\)

Matching type questions: (Match, Column-I and Column-II property) Column-I Column-II (A) Particle nature of light (p) Davisson and Germes (B) Wave nature of light (q) G. P. Thomson (C) Wave nature of slow moving electrons (r) Max. Planck (D) Wave nature of fast moving electrons (s) Huygens (A) \((\mathrm{A}-\mathrm{p}),(\mathrm{B}-\mathrm{q}),(\mathrm{C}-\mathrm{r}),(\mathrm{D}-\mathrm{s})\) (B) \((\mathrm{A}-\mathrm{q}),(\mathrm{B}-\mathrm{r}),(\mathrm{C}-\mathrm{s}),(\mathrm{D}-\mathrm{p})\) (C) \((\mathrm{A}-\mathrm{r}),(\mathrm{B}-\mathrm{s}),(\mathrm{C}-\mathrm{p}),(\mathrm{D}-\mathrm{q})\) (D) \((\mathrm{A}-\mathrm{s}),(\mathrm{B}-\mathrm{r}),(\mathrm{C}-\mathrm{q}),(\mathrm{D}-\mathrm{p})\)

A proton and electron are lying in a box having impenetrable walls, the ratio of uncertainty in their velocities are \(\ldots \ldots\) \(\left(\mathrm{m}_{\mathrm{e}}=\right.\) mass of electron and \(\mathrm{m}_{\mathrm{p}}=\) mass of proton. (A) \(\left(\mathrm{m}_{\mathrm{e}} / \mathrm{m}_{\mathrm{p}}\right)\) (B) \(\mathrm{m}_{\mathrm{e}} \cdot \mathrm{m}_{\mathrm{p}}\) (C) \(\left.\sqrt{\left(m_{e}\right.} \cdot m_{p}\right)\) (D) \(\sqrt{\left(m_{e} / m_{p}\right)}\)

Work function of metal is \(4.2 \mathrm{eV}\) If ultraviolet radiation (photon) having energy \(6.2 \mathrm{eV}\), stopping potential will be........ (A) \(2 \mathrm{eV}\) (B) \(2 \mathrm{~V}\) (C) 0 (d) \(10.4 \mathrm{~V}\)

A proton falls freely under gravity of Earth. Its de Broglie wavelength after \(10 \mathrm{~s}\) of its motion is \(\ldots \ldots \ldots\). Neglect the forces other than gravitational force. \(\left[\mathrm{g}=10\left(\mathrm{~m} / \mathrm{s}^{2}\right), \mathrm{m}_{\mathrm{p}}=1.6 \times 10^{-27} \mathrm{~kg}, \mathrm{~h}=6.625 \times 10^{-34} \mathrm{~J}_{. \mathrm{s}}\right]\) (A) \(3.96 \AA\) (B) \(39.6 \AA\) (C) \(6.93 \AA\) (D) \(69.3 \AA\)

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