Chapter 17: Problem 2364
De-Broglie wavelength of particle moving at a (1/4) th of speed of light having rest mass \(\mathrm{m}_{0}\) is \(\ldots \ldots \ldots\) (A) \(\left\\{(3.87 \mathrm{~h}) /\left(\mathrm{m}_{0} \mathrm{C}\right)\right\\}\) (B) \(\left\\{(4.92 \mathrm{~h}) /\left(\mathrm{m}_{0} \mathrm{C}\right)\right\\}\) (C) \(\left\\{(7.57 \mathrm{~h}) /\left(\mathrm{m}_{0} \mathrm{C}\right)\right\\}\) (D) \(\left\\{(9.46 \mathrm{~h}) /\left(\mathrm{m}_{\circ} \mathrm{C}\right)\right\\}\)
Short Answer
Step by step solution
De-Broglie wavelength formula
Calculate the momentum of the particle
Relativistic mass
Simplify the relativistic mass equation
Calculate the momentum
Calculate the De-Broglie wavelength
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Relativistic Mass
This is expressed with the equation:\[m = \frac{m_0}{\sqrt{1-\frac{v^2}{c^2}}}\]where:
- \( m \) is the relativistic mass.
- \( m_0 \) is the rest mass, the mass of the object when it is at rest.
- \( v \) is the velocity of the object.
- \( c \) is the speed of light.