Chapter 16: Problem 2295
The distance between the first and sixth minima in the diffraction pattern of a single slit, it is \(0.5 \mathrm{~mm}\). The screen is \(0.5 \mathrm{~m}\) away from the Slit. If the wavelength of light is \(5000 \AA\), then the width of the slit will be \(\mathrm{mm}\) (D) \(1.0\) (A) 5 (B) \(2.5\) (C) \(1.25\)
Short Answer
Step by step solution
Understand the formula for minima in a single-slit diffraction pattern.
Convert the given measurements to meters.
Calculate the angle θ using the distance between the first and sixth minima.
Use the formula to find the width of the slit and select the correct answer.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Minima in Diffraction
- \( m \) is the order of the minima (e.g., first, second, etc.).
- \( \lambda \) is the wavelength of the light used.
- \( a \) stands for the width of the slit, which the light passes through.
- \( \theta \) is the angle of diffraction.
Wavelength Conversion
Converting the wavelength from Ångströms to meters involves:
- Since 1 Ångström equals \( 10^{-10} \) meters, for instance, \( 5000 \) Å becomes \( 5 \times 10^{-7} \) meters.
Diffraction Angle Calculation
For small angles, we can approximate:
- \( \tan\theta \approx \sin\theta \approx \frac{y}{L} \).
- \( y \) is the distance between the minima.
- \( L \) is the distance from the slit to the screen where the diffraction pattern is projected.
Slit Width Determination
The calculation involves rearranging:
- \[ a = \frac{m\lambda}{\sin\theta} \]
This approach is highly useful in both experimental physics and theoretical studies where determining geometric parameters of a slit can predict diffraction behaviors.