Chapter 13: Problem 1861
An element \(\mathrm{d} \ell^{-}=\mathrm{dx} \uparrow\) (where \(\mathrm{dx}=1 \mathrm{~cm}\) ) is placed at the origin and carries a large current \(\mathrm{I}=10 \mathrm{Amp}\). What is the mag. field on the Y-axis at a distance of \(0.5\) meter ? (a) \(2 \times 10^{-8} \mathrm{k} \wedge \mathrm{T}\) (b) \(4 \times 10^{8} \mathrm{k} \wedge \mathrm{T}\) (c) \(-2 \times 10^{-8} \mathrm{k} \wedge \mathrm{T}\) (d) \(-4 \times 10^{-8} \mathrm{k} \wedge \mathrm{T}\)
Short Answer
Step by step solution
Biot-Savart Law
Set up the Biot-Savart Integral
Calculate the vector cross product
Determine the distance
Evaluate the Biot-Savart integral
Solve for the magnetic field
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