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Chapter 7: Problem 32

To define a two-dimensional array, _________ size declarators are required.

Short Answer

Expert verified
Answer: Two size declarators are required to define a two-dimensional array.

Step by step solution

01

Understand two-dimensional arrays

A two-dimensional (2D) array is an array of arrays, organizing data in rows and columns, like a table. Each cell in the table can be accessed by specifying its row and column indices, making it easy to store, retrieve and manipulate data structured in this way.
02

Determine the number of size declarators needed

To create a 2D array, one needs to declare both the number of rows (first dimension) and the number of columns (second dimension). Thus, there are two size declarators required for defining a two-dimensional array. So, the answer is that two size declarators are required to define a two-dimensional array.

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Most popular questions from this chapter

In a program you need to store the identification numbers of 10 employees (as ints) and their weekly gross pay (as doubles). A) Define two arrays that may be used in parallel to store the 10 employee identification numbers and gross pay amounts. B) Write a loop that uses these arrays to print each employee's identification number and weekly gross pay.

Consider the following array definition: int values \([5]=\\{4,7,6,8,2\\}\) What does each of the following statements display? cout \(<<\) values \([4]<<\) end; ____________ cout \(<<\text { (values }[2]+\text { values }[3])<<\) end; ____________ cout \(<<++\) values \([1]<<\) end; ____________

T F If an array is partially initialized, the uninitialized elements will contain 鈥済arbage.鈥�

When writing a function that accepts a two-dimensional array as an argument, which size declarator must you provide in the parameter for the array?

Subscript numbering in \(\mathrm{C}_{++}\) always starts at ________.
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