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Chapter 7: Problem 14

When writing a function that accepts a two-dimensional array as an argument, which size declarator must you provide in the parameter for the array?

Short Answer

Expert verified
In order to pass a two-dimensional array to a function, we need to provide enough information about the array's structure within the function's parameters. It is necessary to provide the size declarator for at least one of the dimensions, typically the second dimension, in order to give the function the required information about the array's structure. The first dimension can be left as an empty bracket, allowing for flexibility in the size of that dimension.

Step by step solution

01

Understanding arrays and functions

When passing arrays to a function in programming languages like C or C++, it is important to provide enough information about the array's structure within the function's parameters. For a two-dimensional array, it is necessary to provide the size declarator for at least one of the dimensions, typically the second dimension. The first dimension can be left as an empty bracket, allowing for flexibility in the size of that dimension.
02

Example declaration of a function with a two-dimensional array parameter

Let's look at an example function declaration for a two-dimensional array. Suppose we have a function "processArray" that takes a 2D array of integers with the second dimension having a fixed size of 5: ```c void processArray(int array[][5], int numRows); ``` In this example, the first dimension (numRows) is not specified as it can vary. The second dimension is fixed, with a size of 5.
03

Conclusion

When writing a function that accepts a two-dimensional array as an argument, you need to provide at least one size declarator, usually the second dimension. The first dimension can be left as an empty bracket, allowing for flexibility in the size of that dimension.

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