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Pentane (C5H12)is a liquid with a density of 0.626 g/mL near

258C. Find the true mass of pentane when the mass in air is 14.82 g.

Assume air density 0.001 2gm/L.

Short Answer

Expert verified

The true mass of pentane when the mass in the air is 14.82 g is C5H12=14.79g.

Step by step solution

01

Defining the formula for determining the true mass

Buoyancy error: It occurs when the density of the object being weighed is not equal to the density of the standard mass.

m=m'(1-dadw)(1-dad)

Here,

dais the density of air,

dwis the density of the calibration weights, and

d is the density of the object being weighed.

02

Step 2: Calculating the total density of pentane

Given:

The density of C5H12=0.626g/mL.

Air density =0.0012g/mL.

The mass of pentane in air =14.82g .


The total density =0.626g/mL+0.0012g/mL.

The total density =0.6272g/mL.

03

Step 3: Calculating the volume of pentane

Volume=massdensityVolume"=14.82g0.6272g/mLVolume=23.63mL.

Calculation of the true mass:

The true mass of C5H12=volume density.

The true mass of C5H12=23.63mL×0.626g/mL.

The true mass of C5H12=14.79g.

Thus, the true mass of pentane under the given condition is C5H12=14.79g.

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