/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q6P Explain the principle of operati... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Explain the principle of operation of an electronic balance.

Short Answer

Expert verified

For the working principle of electronic scales in the highest precision class, electromagnetic force compensation is a suitable measurement principle

Step by step solution

01

Defining an electronic balance

Many high school and college chemistry departments now feature electronic balances as standard equipment. They enable users to swiftly and precisely quantify the mass of a substance at a level of precision that is impossible to attain with standard balances.

02

Step 2: Explaining the principle of operation

Electronic balances are considered basic equipment in chemistry departments and are used to obtain precise weight readings.

  • They have 0.1-gram readability.
  • To weigh a chemical, we usually start by placing a clean vessel on the balance pan and pressing the tare button to remove the vessel's mass.
  • The chemical is then added to the vessel, and its mass is determined.

To balance a load on the pan, an electronic balance uses electromagnetic force correction.

A clean receiving jar should be placed on the balance pan before weighing a chemical.

The tare is the bulk of the empty vessel. The vessel should be filled with the chemical, and the mass should be checked.

Chemicals should never be placed directly on the weighing pan to preserve the balance from corrosion.

To operate an electronic balance, the object put on it pushes the pan down with a force of m * g, where m is the object's mass, and g is the acceleration due to gravity.

To precisely negate the motion of the pan, the balance generates an electric current.

The current's magnitude indicates the magnitude of the mass placed on it.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

For chemical disposal, why is dichromate converted toCr(OH)3(s)

Water was drained from a buret between the 0.12- and 15.78-mLmarks. The apparent volume delivered was15.78-0.12=15.66mL. Measured in the air at22°C the mass of water delivered was15.569g. What was the true volume?

A sample of ferric oxide (Fe2O3, density 5.24g/mL) obtained from ignition of a gravimetric precipitate weighed 0.2961gin the atmosphere. What is the true mass in vacuum?

(a) Effect of altitude on electronic balance. If an object weighsgrams at distance ra from the center of the Earth, it will weigh mb=ma(ra2/rb2)when raised to role="math" localid="1663305908411" rb. An object weighs 100.0000g on the first floor of a building at ra=6370km. How much will it weigh on the tenth floor, which is 30mhigher?

(b) If you press the "calibrate" button of the electronic balance on the tenth floor before weighing the object, the observed mass will be 100.0000g. Why?

(a) The equilibrium vapor pressure of water at \({20^\circ }{\rm{C}}\) is \(2330\)Pa. What is the vapor pressure of water in the air at \({20^\circ }{\rm{C}}\)if the relative humidity is \(42\% \) ? (Relative humidity is the percentage of the equilibrium water vapor pressure in the air.)

(b) Use note \({\bf{13}}\) for Chapter \({\bf{2}}\) at the end of the book to find the air density\(({\rm{g}}/{\rm{mL}}\),not \({\rm{g}}/{\rm{L}})\)under the conditions of part\(\left( {\bf{a}} \right)\)if the barometric pressure is\(94.0{\rm{kPa}}\).

(c) What is the true mass of water in part \(\left( {\bf{b}} \right)\)if the mass in air is\(1.0000\;{\rm{g}}\)?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.