/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q6-DE Which will be more soluble (mole... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 0: Q6-DE (page 1)

Which will be more soluble (moles of metal dissolved per litre of solution),Ba(IO3)2(Ksp=1.5x10-9)orCa(IO3)2(Ksp=7.1x107) ? Give an example of a chemical reaction that might occur that would reverse the predicted solubilities.

Short Answer

Expert verified

Ca(IO3)2is found to be more soluble.

Step by step solution

01

solubility product

The more soluble component in the given compounds must be anticipated, and examples must be provided.

Solubility product (Ksp):

It is defined as the mathematical product of the dissolved ion's concentration raised to the power of its stoichiometric coefficient.

MyXzsyMz+aq+zXy-aqKsp=MzyXy-z

02

check solubility product value

The solubility product Kspfor,

BaIO32=1.5x10-9BaIO32=7.1x10-7

The solubility product value is more for CaIO32than for BaIO32. As a result, it should be more soluble and have the same stoichiometry. If the stoichiometry is not the same, compare the Kspvalues directly. If, for example, barium salt can form ion pairs, but calcium salt cannot, your forecast may be incorrect.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

25. Write a mass balance for a solution ofFe2(SO4)3if the species

areFe3+,FeOH2+,Fe(OH)2+,FeSO4+,SO42-androle="math" localid="1663402048017" SO42-.

When you flip a coin, the probability of its landing on each side isin Equations 28-2 and 28-3. If you flip it times, the expected number of heads equals the expected number of tailsThe expected standard deviation for flips is. From Table 4-1, we expect thatof the results will lie withinand of the results will lie within.

(a) Find the expected standard deviation for the number of heads incoin flips.

(b) By interpolation in Table 4-1, find the value of that includesof the area of the Gaussian curve. We expect thatof the results will lie within this number of standard deviations from the mean.

(c) If you repeat thecoin flips many times, what is the expected range for the number of heads that includesof the results? (For example, your answer might be, "The rangetowill be observedof the time.")

List the steps in a chemical analysis.

The iodide (I-)content of a commercial mineral water was measured by two methods that produced wildly different results. Method A found0.23 milligrams of (I-)per litermg/Land method B found 0.009mg/L. When Mn2+ was added to the water, the I- content found by method A increased each time that moreMn2+was added, but results from method B were unchanged. Which of the Terms to Understand describes what is occurring in these measurements? Explain your answer. Which result is more reliable?

What is the purpose of the trap in Figure 2-17 and the watch glass in Figure 2-20?
See all solutions

Recommended explanations on Chemistry Textbooks

Physical Chemistry

Read Explanation

Chemical Reactions

Read Explanation

Nuclear Chemistry

Read Explanation

Chemical Analysis

Read Explanation

The Earths Atmosphere

Read Explanation

Ionic and Molecular Compounds

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.