/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q27P The variation of refractive inde... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 20: Q27P (page 527)

The variation of refractive index, n, with wavelength for fused silica is given by

n2鈥�1=(0.6961663)位2位2鈥�(0.0684043)2+(0.4079426)位2位2鈥�(0.1162414)2+(0.8974794)位2位2鈥�(9.896161)2

where 位 is expressed in 渭尘.

(a) Make a graph of n versus 位 with points at the following wavelengths: 0.2,0.4,0.6,0.8,1,2,3,4,5, and 6渭尘.

(b) The ability of a prism to spread apart (disperse) neighboring wavelengths increases as the slope dn/诲位increases. Is the dispersion of fused silica greater for blue light or red light?

Short Answer

Expert verified

(a) The wavelengths of 0.2,0.4,0.6,0.8,1,2,3,4,5, and 6渭尘 is


(b) The dispersion of fused silica is greater for blue light ( 400 nm ) than red light ( 600 nm ).

Step by step solution

01

Definition of wavelenght

  • The wavelength of a waveform signal conveyed in space or down a wire is the distance between identical points (adjacent crests) in adjacent cycles.
02

Determine the following wavelengths: 0.2,0.4,0.6,0.8,1,2,3,4,5, and 6μm.

A graph depicting the relationship between n and 位It must be marked.

The graph was created using the formula provided.

Wavelength=位0n

位0is the wavelength in vacuum

n is the refraction inden

(a)

For blue light or red light, the dispersion of fused silica is larger.

03

Determine the dispersion of fused silica greater for blue light or red light

(b)

For blue light or red light, the dispersion of fused silica is larger.


dn诲位a wavelength of blue light~400nm then the red light comes on ~600nm.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Explain how the difference voltage in Figure 20-37 reduces noise from source flicker.

The prism shown here is used to totally reflect light at a90掳angle. No surface of this prism is silvered. Use Snell's law to explain why total reflection occurs. What is the minimum refractive index of the prism for total reflection?

The true absorbance of a sample is 1.000, but the mono chromator passes 1.0% stray light. Add the light coming through the sample to the stray light to find the apparent transmittance of the sample. Convert this answer back into absorbance and find the relative error in the calculated concentration of the sample.

The prism shown here is used to totally reflect light at a90掳angle. No surface of this prism is silvered. Use Snell's law to explain why total reflection occurs. What is the minimum refractive index of the prism for total reflection?

Explain how a laser generates light. List important properties of laser light.
See all solutions

Recommended explanations on Chemistry Textbooks

Physical Chemistry

Read Explanation

Nuclear Chemistry

Read Explanation

Chemical Analysis

Read Explanation

Chemical Reactions

Read Explanation

Organic Chemistry

Read Explanation

The Earths Atmosphere

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.