/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q10P 聽What is a Jones reductor and w... [FREE SOLUTION] | 91影视

91影视

What is a Jones reductor and what is it used for?

Short Answer

Expert verified

Jones reductor is a reducing substance that can be used to lower the oxidation state of a metal ion in an aqueous solution

Step by step solution

01

Definition of Jones reductor.

A device that is used to chemically decrease liquids, such as ferric salt solutions, by pouring the solution into a vertical tube containing granular zinc.

02

Determine the Jones redactor and uses.

  • Jones reductor is a column that contains zinc coated with zinc amalgam (solution with mercury).

  • Analyte is pre-reduced by passing through the Jones reductor with sulfuric acid as a solvent Analytes that can be reduced with Jones reductor are Fe3+,Sn4andMnO4Uses:

  • A Jones reductor is a reducing substance that can be used to lower the oxidation state of a metal ion in aqueous solution.

  • A zinc amalgam is the active ingredient. It can be used to make solutions of ions that are promptly oxidised when exposed to air, such as Chromium(II), Cr2, and uranium(III),U3+.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Here is a description of an analytical procedure for superconductors containing unknown quantities of Cu(I),Cu(II), Cu(III), and peroxide (O22-) : 33The possible trivalent copper and/or peroxide type oxygen are reduced by Cu(I) when dissolving the sample (ca .50 mg) in deoxygenated HCl solution ( 1 M) containing a known excess of monovalent copper ions (ca.25mgCuCI) . On the other hand, if the sample itself contained monovalent copper, the amount of Cu(I) in the solution would increase upon dissolving the sample. The excess Cu(I) was then determined by coulometric back titration... in an argon atmosphere." The abbreviation "ca." means "approximately." Coulometry is an electrochemical method in which the electrons liberated in the reactionCu+Cu2++eare measured from the charge flowing through an electrode. Explain with your own words and equations how this analysis works.

Aqueous glycerol solution weighing 100.0m gwas treated with 50.0 mL of 0.083 7 M Ce4+in 4 MHCIO4at 60for15minto oxidize glycerol to formic acid.

CH2-CH-CH2|||OHOHOH HCO2H

Glycerol Formic acid

FM92.095

The excess Ce4+ required 12.11mL of 0.044 8 MFe2+to reach a ferroin end point. Find wt%glycerol in the unknown.

The Kjeldahl analysis in Section 11-8 is used to measure the nitrogen content of organic compounds, which are digested in boiling sulfuric acid to decompose to ammonia, which, in turn, is distilled into standard acid. The remaining acid is then back-titrated with base. Kjeldahl himself had difficulty in 1880 discerning by lamplight the methyl red indicator end point in the back titration. He could have refrained from working at night, but instead he chose to complete the analysis differently. After distilling the ammonia into standard sulfuric acid, he added a mixture of KIO3and KI to the acid. The liberated iodine was then titrated with thiosulfate, using starch for easy end-point detection even by lamplight. Explain how the thiosulfate titration is related to the nitrogen content of the unknown. Derive a relationship between moles ofNH3 liberated in the digestion and moles of thiosulfate required for titration of iodine.

Two possible reactions of MnO4-withH2O2to produceO2andareMn+

Scheme:MnO4-Mn2+H2O2O2

Scheme:MnO4-O2+Mn2+H2O2H2O

(a) Complete the half reactions for both schemes by adding e+and H2Oand H+write a balanced net equation for each scheme.

(b) Sodium peroxyborate tetrahydrate, NaBO34H2O(FM153.86)produces H2O2when dissolved in acid BO3-+2H2OH2O2+H2BO3-. To decide whether Scheme 1 or 2 Schemeoccurs student at the U.S. Naval academy weighed 0.123gNaBO3.2H2Ointo a 100mLvolumetric flask added 20mLof 1MH2SO4and diluted to the mark with H2O. Then they titratedof this solution with0.01046MKMnO4until the first pale pink color persisted. How may mL ofKMnO4are required in Scheme 1and 2 Scheme?

(The Scheme 1stoichiometry was observed).

Consider the titration of 100.0mLof 0.0100MCe4+ in 1MHClO4by 0.0400MCu+ to give Ce3+ and Cu2+ , using Pt and saturated Ag | AgCl electrodes to find the end point.

(a) Write a balanced titration reaction.

(b) Write two different half-reactions for the indicator electrode.

(c) Write two different Nernst equations for the cell voltage.

(d) Calculate Eat the following volumes ofCu+:1.00,12.5,24.5,25.0,25.5,30.0 and 50.0 mL. Sketch the titration curve.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.