Q9P Consider a sample that contains ... [FREE SOLUTION]

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Chapter 5: Q9P (page 114)

Consider a sample that contains analyte at the detection limit defined in Figure. Explain the following statements: There is approximately a $1 %$ chance of falsely concluding that a sample containing no analyte contains analyte above the detection limit. There is a $50 %$ chance of concluding that a sample that really contains analyte at the detection limit does not contain analyte above the detection limit.

Short Answer

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The following statements was explained.

1. Above the detection limit approximately

$1 %$

chance of falsely concluding that the sample does contain no analyte.

2. Above the detection limit approximately $50 %$ chance of concluding that the sample doesn't contains analyte.

Step by step solution

The detection limit

The concentration of an analyte that produces a signal with a standard deviation three times that of a blank signal.

The minimum detectable concentration $= \frac{3 s}{m}$

Where,

$S =$ Standard deviation.

$m =$ Slope of linear calibration curve.

Explanation of statements

The first statement means that since there is approximately $1 %$ chance of false negative results showing up, there will also be approximately $1 %$ of samples (that do NOT contain the analytes) that will respond with a signal above the detection limit.

For the second statement -- which is a hypothetical situation for false positive results -- means that $50 %$ of the samples containing the analyte with a signal going below the limit of detection.