/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} QIE A solution contains 63 different... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A solution contains 63 different conjugate acid-base pairs.

Among them is acrylic acid and acrylate ion, with the equilibrium ratio [acrylate]/[acrylic acid]5 0.75. What is the pH of the solution?

H2C=CHCO2HpKa=4.25

Short Answer

Expert verified

The pH of the solution using Henderson-Hasselbalch equation and was found to be 4.13

Step by step solution

01

Step 1: Define the term Henderson-Hasselbalch Equation.

Equation of Henderson-Hasselbalch. pH, pKa, and molar concentration (concentration in moles per litre) are all linked by the Henderson-Hasselbalch equation: apH=logA-/HA+pK a The molar concentration of a conjugate base isA-.HA= molar concentration of a weak acid that has not been dissociated (M).

02

Calculate the ph of the solution.

Equilibrium ratio=0.75

pKa=4.25

The pHof the solution can be calculated as,

role="math" localid="1654769713942" pH=pKa+logA-HApH=4.25+log0.75pH=4.13

The pH of the solution=4.13

The pH of the solution using Henderson-Hasselbalch equation and was found to be 4.13.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Which of the following bases would be most suitable for preparing a buffer of pH9.00?

(i) NH3(ammonia,Kb=1.76×10-5);

(ii) role="math" localid="1654764490555" C6H5NH2(aniline,role="math" localid="1654764515634" C6H5NH2 );

(iii)H2NNH2(hydrazine,Kb=1.05×10-6)));

(iv) C6HsNH2(pyridine,Kb=1.58×10-9) ).

Calculate the pH of a solution prepared by mixing 0.0800mol of chloroacetic acid plus0.0400mol of sodium chloroacetate in1.00L of water.

(a) First do the calculation by assuming that the concentrations of HA andA- equal their formal concentrations.

(b) Then do the calculation, using the real values of and in the solution.

(c) Using first your head, and then the Henderson-Hasselbalch equation, find the pH of a solution prepared by dissolving all the following compounds in one beaker containing a total volume of1.00L:0.180molCICHCOO2H,0.020molCICHCHO2Na20.080molHNO3,and0.080molCa(OH)2. Assume thatCa(OH)2 dissociates completely.

(a) Write the chemical reactions whose equilibrium constants areKband Kafor imidazole and imidazole hydrochloride respectively.

(b) Calculate the pH of a solution prepared by mixing 1.00gof imidazole with 1.00gof imidazole hydrochloride and diluting torole="math" localid="1655093511290" 100.0mL .

(c) Calculate the pH of the solution if 2.30mLof 1.07MHCIO4are added.

(d) How many milliliters of1.07MHCIO4should be added to of imidazole to give a pH ofrole="math" localid="1655093364034" 6.993?

Barbituric acid dissociates as follows:

(b)Calculate the pH and fraction of dissociation of 10-10.00 M barbituric acid.

Select a compound from Table 9-2 that you could use to make 250mLof 0.2Mbuffer with a pH of 6.0. Explain how you would make the buffer.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.