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Which of the following bases would be most suitable for preparing a buffer of pH9.00?

(i) NH3(ammonia,Kb=1.7610-5);

(ii) role="math" localid="1654764490555" C6H5NH2(aniline,role="math" localid="1654764515634" C6H5NH2 );

(iii)H2NNH2(hydrazine,Kb=1.0510-6)));

(iv) C6HsNH2(pyridine,Kb=1.5810-9) ).

Short Answer

Expert verified

Ammonia is found to be most suitable base, because it has pKavalue that is closest for the preparation of buffer at pH=9.00

Step by step solution

01

Step 1: Define the term Conjugate acid-base pair.

Consider the conjugate acid-base pair HA and its equivalent base. Because they are linked to proton gain or loss, they are collectively known as conjugate acid-base pair.

A weak base is a conjugate base of a weak acid.

A weak acid is a conjugate acid of a weak basepk

The negative logarithm of an equilibrium constant is called as pK

02

Calculate the isoionic PH

List of bases with their respective pKavalue

Compound pKa(for conjugate acid)

Ammonia 9.24

Aniline 4.60

Hydrazine 8.02

Pyridine 5.20

From the above given list, it can be seen that Ammonia has pKavalue that is closest for the preparation of buffer at role="math" localid="1654765470337" pH=9.00

Hence,

Ammonia can be used as suitable base for preparing buffer of pH=9.00

Reason for incorrect option:

Aniline and other two bases can be toxic even though if they had role="math" localid="1654765611815" pKavalue near to the given pH

Hydrazine and Pyridine cannot be used as suitable buffer since theirpKa values aren't close to the that is required for the preparation of buffer.

Conclusion

Ammonia is found to be most suitable base, because it has pKa value that is closest for the preparation of buffer atpH=9.00

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