Q42P Chlorate (CIO-3), chlorite (CIO-... [FREE SOLUTION]

Chapter 22: Q42P (page 603)

Chlorate $({CIO}^{-}_{3})$ , chlorite $({CIO}^{-}_{2})$ , bromate $({BrO}^{-}_{3})$ , and iodate $({IO}^{-}_{3})$ can be measured in drinking water at the 1-ppb level with 1% precision by selected reaction monitoring. Chlorate and chlorite arise from ${CIO}_{2}$ used as a disinfectant. Bromate and iodate can be formed from ${Br}^{-}$ or $I^{-}$ when water is disinfected with ozone $(O_{3})$ . For the highly selective measurement of chlorate, the negative ion selected by Q1 in Figure 22-33 is m/z 83 and the negative ion selected by Q3 is m/z 67. Explain how this measurement works and how it distinguishes ${CIO}_{3}^{-}$ from ${CIO}_{2}^{-}$ , ${BrO}_{3}^{-}$ , and ${IO}_{3}^{-}$

Short Answer

Expert verified

The answer is not given in the drive.

Step by step solution

Test CIO3-:

Test whether ${CIO}_{3}^{-}$ can be distinguished from all three other compound in drinking water, the m/z of all of the compounds should be computed.

${CIO}_{2}^{-}$ has m/z of 67 which pass through third quadrupole, it wouldn鈥檛 have pass through second quadrupole.

further explanation:

When ${CIO}_{3}^{-}$ passes through the second quadrupole, it undergoes collisionally activated dissociation, breaking into fragments. One of the possible fragments to be formed is ${CIO}_{2}^{-}$ fragment. The only fragment that would be able to leave the third quadrupole, reaching the detector.