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A 1.000-g sample of unknown gave 2.500 g of bis (dimethylglyoximate)nickel (II) (FM 288.91) when analyzed by Reaction 27-7. Find the weight percent of Ni in the unknown.

Short Answer

Expert verified

The weight percent of Ni is 0.5079.

Step by step solution

01

calculate the moles of bis (dimethylglyoximate)nickel (II):4

In this task we have a 1 g of sample which gave 2.5 g of bis (dimethylglyoximate)nickel(II) (M=288.91 g/mol) when analyzed by Reaction 27-7. Here we will find the weight percent of Ni in the unknown sample.

Calculate the moles of bis (dimethylglyoximate)nickel(II):

n=mMn=2.5g288.91g/moln=8.6532×10-8mol

consider that n (bis (dimethylglyoximate)nickel(II)) =n (Ni)

02

calculate mass and weight percent of Ni:

The mass of Ni is,

m(Ni)=n×Mm(Ni)=(8.6532×10-8mol)×58.6934g/mol

The weight percent of Ni is,

wt%=mNimsamplewt%=0.50788g1gwt%=0.5079

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