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The transmittance of a 0.010 M solution of a compound in a 0.100-cm-path length cell is .T=8.23%Find the absorbance (A) and the molar absorptive (ε).

Short Answer

Expert verified

The value of absorbance is≈1.08

The value of molar absorptive is1.08x1103M-1cm-1

Step by step solution

01

Calculate absorbance:

Equation for absorbance is

A=-logT →(1)

To find transmittance the equation isT=%T100%

Substitute 8.23%for%in above equation,

T=%T100%=0.0823

Substitute the value of transmittance in (1),

A=-logTA=-log0.0823≈1.08

The value of absorbance is≈1.08

02

Calculate molar absorptive:

Equation to calculate ε is,

ε=Abc →(2)

Given,

c=0.010Mb=0.100cmA=1.08

Substitute in equation (2),

ε=1.080.0100cm0.010Mε=1.08x103M-1cm-1

The value of molar absorptive is1.08x103M-1cm-1

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