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Now we use Solver to find Kfor the previous problem. The only absorbing species at 332 nmis the complex, so, from Beer鈥檚 law $\mathbf{\left[}\mathbf{complex}\mathbf{\right]}\mathbf{=}\mathbf{A}\mathbf{/}\mathbf{蔚}\mathbf{(}\mathbf{becausepathlength}\mathbf{=}\mathbf{1}\mathbf{.}\mathbf{000}\mathbf{cm}\mathbf{)}\mathbf{.}{\mathbf{I}}_{\mathbf{2}}$is either free or bound in the complex,so $\mathbf{\left[}{\mathbf{I}}_{\mathbf{2}}\mathbf{\right]}\mathbf{=}\mathbf{[}{\mathbf{I}}_{\mathbf{2}}{\mathbf{]}}_{\mathbf{tot}}\mathbf{-}\mathbf{[}\mathbf{complex}\mathbf{]}\mathbf{.}$There is a huge excess of mesitylene, so$\mathbf{\left[}\mathbf{mesitylene}\mathbf{\right]}$$\mathbf{鈮�}\mathbf{[}\mathbf{mesitylene}{\mathbf{]}}_{\mathbf{tot}}$

$\mathit{K}\mathbf{=}\frac{\left[complex\right]}{\left[l_2\right]\left[mesitylene\right]}\mathbf{=}\frac{\mathbf{A}\mathbf{/}\mathbf{蔚}}{\left({\left[l_2\right]}_{tot}-A/蔚\right){\left[mestitylene\right]}_{\mathbf{t}\mathbf{o}\mathbf{t}}}$

The spreadsheet shows some of the data. You will need to use all the data. Column A contains [mesitylene] and column B contains ${\left[l_2\right]}_{\mathbf{tot}}$_. Column C lists the measured absorbance. Guessa value of the molar absorptivity of the complex,$\mathbf{蔚}\mathbf{,}\mathbf{in}\mathbf{}\mathbf{cell}\mathbf{}\mathbf{A}\mathbf{7}\mathbf{.}$Then compute the concentration of the complex $\left(=A/蔚\right)$in column D. The equilibrium constant in column $\mathbf{E}\mathbf{}\mathbf{is}\mathbf{}\mathbf{given}\mathbf{}\mathbf{by}\mathbf{}\mathbf{E}\mathbf{2}\mathbf{}\mathbf{=}$$\mathbf{\left[}\mathbf{complex}\mathbf{\right]}\mathbf{/}\mathbf{\left(}\mathbf{\right[}{\mathbf{I}}_{\mathbf{2}}\mathbf{\left]}\mathbf{\right[}\mathbf{mesitylene}\mathbf{\left]}\mathbf{\right)}\mathbf{=}\mathbf{\left(}\mathbf{D}\mathbf{2}\mathbf{\right)}\mathbf{/}\mathbf{\left(}\mathbf{\right(}\mathbf{B}\mathbf{2}\mathbf{-}\mathbf{D}\mathbf{2}\mathbf{)}\mathbf{*}\mathbf{A}\mathbf{2}\mathbf{)}\mathbf{.}$

should we minimize with Solver? We want to vary蔚in cell A7 until the values of Kin column E are as constant as possible. We would like to minimize a function like $\mathbf{鈭�}\mathbf{(}{\mathbf{K}}_{\mathbf{i}}\mathbf{-}{\mathbf{K}}_{\mathbf{average}}{\mathbf{)}}^{\mathbf{2}}$, where K_iis the value in each line of the table and Kaverage is the average of all computed values. The problem with $\mathbf{鈭�}\mathbf{(}{\mathbf{K}}_{\mathbf{i}}\mathbf{-}{\mathbf{K}}_{\mathbf{average}}{\mathbf{)}}^{\mathbf{2}}$is that we can minimize this function simply by making ${\mathit{K}}_{\mathbf{i}}$very small, but not necessarily constant. What we really want is for all the ${\mathit{K}}_{\mathbf{i}}$to be clustered around the mean value. A good way to do this is to minimize the relative standard deviationof the K, which is (standard deviation)/average. In cell E5we compute the average value of Kand in cell E6the standard deviation. Cell E7contains the relative standard deviation. Use Solver to minimize cell E7by varying cell A7. Compare your answer with that of Problem 19-13.

Step by step solution

01

Define molar absorptivity.

It is measurement of how strongly a chemical species absorbs light at a given wavelength.

02

Draw a graph.

03

Calculate equilibrium constant.

From the graph, slope is -0.464. The slope is 鈥揔.

So, K = 0.464.

Using function of intercept, we calculate y- intercept.

So, the intercept is 4.984 .10³

04

Calculate molar absorptivity.

$$\begin{gathered} \stackrel{\text{'}}{\mathrm{o}}=\frac{\mathrm{y}-\mathrm{intercept}}{\mathrm{K}} \\ \stackrel{\text{'}}{\mathrm{o}}=\frac{4.984.{10}^3}{0.464} \\ \stackrel{\text{'}}{\mathrm{o}}=1.074.{10}^4{\mathrm{M}}^{-1}{\mathrm{cm}}^{-1} \end{gathered}$$

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