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Chapter 8: QCE (page 182)

Using activities, find $[{Ag}^{+}]$ in $0.060 MKSCN$ saturated with $AgSCN (s)$

Short Answer

Expert verified

The concentration of ${Ag}^{+}$ ion in 0.060MKSCN is $2.9 脳 10^{- 11} M$

Step by step solution

01

Define the formula for activity species.

Any species' activity value is calculated by multiplying its concentration by its activity coefficient.

For a species C, the activity is given by

$A_{c} = [C] 纬_{c}$

where,

A - Activity

[c] - Concentration

- Activity coefficient.

02

Calculate the activity species.

Given

$0.060 {MKSCN}^{- 1}$ saturated with ${AgSCN}_{(s)}$

The ionic strength $(渭)$ is $0.060 M$ from KSCN,

The solubility product expression

$渭 = 0.060 M K_{SP} = [{Ag}^{+}] 纬_{{Ag}^{+}} [{SCN}^{-}] 纬_{SCN} = 1.1 脳 10^{- 12} At and 纬_{SCN} = 0.80 纬_{A g^{-}} = 0.79$

Substitute the values of concentration and activity coefficients into the solubility product expression

$K_{SP} = [{Ag}^{+}] (0.79) [0.060] (0.80) = 1.1 脳 10^{- 12} [{Ag}^{+}]$

The concentration of ${Ag}^{+}$ ion in $0.060 MKSCN is 2.9 脳 10^{- 11} M$

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Most popular questions from this chapter

Explain why the solubility of an ionic compound increases as

the ionic strength of the solution increases (at least up to ,0.5 M ).

Including activity coefficient, find the concentration of ${Ba}^{2 +}$ in $0.100 M {({CH}_{3})}_{4} {NIO}_{3}$ solution saturated with $Ba {({IO}_{3})}_{2}$ .

What is the ionic strength of $1 {mMCaCl}_{2}$ ?

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15.Activity coefficient of a neutral molecule. We use the approximation

that the activity coefficient $(纬)$ of neutral molecules is 1.00.A more accurate relation is $濒辞驳纬 = 办渭$ , where $渭$ is ionic strengthand $k 鈮� 0.11$ for ${NH}_{3}$ and ${CO}_{2}$ and $k 鈮� 0.2$ for organic molecules.With activity coefficients for $HA, A^{-}$ ,and $H^{+}$ , predict the value ofthe quotient below for benzoic acid $^{(HA = C_{6} H_{5} {CO}_{2} H)}$ The observed quotient is $^{0.63 卤 0.03}$ .

Concentration quotient $= \frac{\frac{[H^{+}] [A^{-}]}{[HA]} (at 渭 = 0)}{\frac{[H^{+}] [A^{-}]}{[HA]} (at 渭 = 0.1 M)}$

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