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Chapter 8: Q4 TY (page 167)

By interpolation, find $纬$ for $H^{+}$ when $渭 = 0.06 M$ .

Short Answer

Expert verified

The activity coefficient value for $H^{+}$ ion is 0.854.

Step by step solution

01

Concept used.

Extended Debye-Huckel equation:

The extended Debye-Huckel equation describes the link between activity coefficient and ionic strength.

$纬$ -activity coefficient of ion

$渭$ -ionic strength of solution

$蟽$ -size of ion

02

Step 2: Calculate the value of γ.

The activity coefficient and ionic strength values for ion:

The linear interpolation:

$\frac{U n k n o w n i n t e r v a l}{鈭� 纬} = \frac{k n o w n i n t e r v a l}{鈭� 纬} \frac{0.83 - 1}{0.83 - 0.86} = \frac{0.1 - 0.06}{0.1 - 0.05} 0.83 - 纬 = \frac{0.04}{0.05} (- 0.03) - 纬 = - 0.024 - 0.83 = - 0.854 纬 = 0.854$

The activity coefficient value for $H^{+}$ ion is 0.854.

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Most popular questions from this chapter

Solubility with Activity: Find the concentration of the major species in a saturated aqueous solution of $LiF$ . Consider these reactions:

$LiF (s) 謴 {Li}^{+} + F^{-} K_{sp} = [{Li}^{+}] 纬_{{Li}^{+}} [F^{-}] 纬_{F^{-}} LiF (s) 謴 LiF (aq) K_{ionpair} = [LiF (aq)] 纬尝颈贵 (aq) F^{-} + H_{2} O 謴 HF + {OH}^{-} K_{b} = \frac{K_{w}}{K_{a}} (forHF) H_{2} O \overset{K_{w}}{謴} H^{+} + {OH}^{-} K_{w} = [H^{+}] 纬_{H^{+}} [{OH}^{-}] 纬_{{OH}^{-}}$

Look up the equilibrium constants in the appendixes and write their pK values. The ion pair reaction is the sum of localid="1654945209684" $LiF (s) 謴 {Li}^{+} + F^{-}$ from the Appendix ${FandLi}^{+} 謴 LiF (aq)$ from Appendix J. write the equilibrium constant expressions and the charge and mass balance.
Create a spreadsheet that uses activities to find the concentration of all species and the ionic strength. Use pH and pOH as independent variables to estimate. It does not work to choose pH and pLi because their concentration fixes that of the other through the relation $K_{sp} = [{Li}^{+}] 纬_{{Li}^{+}} [F^{-}] 纬_{F^{-}}$

Find the activity (not the activity coefficient) of the ${(C_{3} H_{7})}_{4} N^{+}$ (tetra propylammonium) ion in a solution containing ${(C_{3} H_{7})}_{4} N^{+} {Br}^{-} plus 0.0050 M {({CH}_{3})}_{4} N^{+} {CI}^{-}$

14.The temperature-dependent form of the extended Debye-

H眉ckel equation 8-6 is

$l o g 纬 = \frac{(- 1.825 脳 10^{6}) {(蔚 T)}^{- 3 / 2} Z^{2} \sqrt{渭}}{1 + 伪 \sqrt{渭} / (2.00 \sqrt{蔚 T})}$

where $蔚$ is the (dimensionless) dielectric constant* of water, T is

temperature (K), Z is the charge of the ion, $渭$ is ionic strength $(mol / L)$ ,and $伪$ is the ion size parameter (pm). The dependence of 麓

on temperature is

role="math" localid="1654916203154" $蔚 = 79.755 e^{(- 4.6 脳 10^{- 3}) (T - 293.15)}$

Calculate the activity coefficient of

{SO}_{4}^{2 -}

50.00 掳 C

渭 = 0.100 M

. Compare your value with the one in Table 8-1.

Using activities, find $[{Ag}^{+}]$ in $0.060 MKSCN$ saturated with $AgSCN (s)$

Using activities, calculate the pH and concentration of $H^{+}$ in 0.050MLiBr at $25 掳 C$ .

See all solutions

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