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The following reactions are known to occur in the body \(\mathrm{CO}_{2}+\mathrm{H}_{2} \mathrm{O} \leftrightarrow \mathrm{H}_{2} \mathrm{CO}_{3} \leftrightarrow \mathrm{H}^{+}+\mathrm{HCO}_{3}^{-1}\) If \(\mathrm{CO}_{2}\) escapes from the system a. \(\mathrm{pH}\) will decrease b. Hydrogen ion concentration will diminish c. \(\mathrm{H}_{2} \mathrm{CO}_{3}\) concentration will remain unchanged d. the forward reaction will be favoured.

Short Answer

Expert verified
The hydrogen ion concentration diminishes (option b is correct).

Step by step solution

01

Understanding the Reaction Equilibrium

The given reactions show a chemical equilibrium where carbon dioxide (\(\mathrm{CO}_2\)) dissolves in water to form carbonic acid (\(\mathrm{H}_2\mathrm{CO}_3\)), which then dissociates into hydrogen ions (\(\mathrm{H}^+\)) and bicarbonate ions (\(\mathrm{HCO}_3^{-1}\)). This equilibrium can shift according to Le Chatelier's principle if any component in the system changes.
02

Analyzing the Effect of CO2 Escape

When \(\mathrm{CO}_2\) escapes from the system, it reduces the concentration of \(\mathrm{CO}_2\). According to Le Chatelier's principle, a system at equilibrium will adjust to counteract the change, which means the equilibrium will shift to the left to replace the lost \(\mathrm{CO}_2\).
03

Consequences of Shift to the Left

As the equilibrium shifts to the left, more \(\mathrm{H}_2\mathrm{CO}_3\) will convert back into \(\mathrm{CO}_2\) and \(\mathrm{H}_2\mathrm{O}\). Consequently, this will reduce the dissociation of \(\mathrm{H}_2\mathrm{CO}_3\) to \(\mathrm{H}^+\) and \(\mathrm{HCO}_3^{-1}\), decreasing the \(\mathrm{H}^+\) concentration.
04

Understanding Impact on pH and Hydrogen Ion Concentration

As the \(\mathrm{H}^+\) concentration decreases, the pH of the solution increases because pH is inversely related to hydrogen ion concentration. Thus, instead of decreasing, as \(\mathrm{CO}_2\) escapes, the pH will actually increase. Hydrogen ion concentration does diminish, opposing option a and confirming option b.
05

Evaluating Options for Changes in "H2CO3" Concentration and Reaction Direction

Since the equilibrium shifts to the left when \(\mathrm{CO}_2\) is removed, the \(\mathrm{H}_2\mathrm{CO}_3\) concentration will reduce rather than stay unchanged, opposing option c. Moreover, the backward reaction is favored, opposing option d, since more \(\mathrm{CO}_2\) will be generated as \(\mathrm{H}_2\mathrm{CO}_3\) breaks down.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reaction Equilibrium
In chemistry, reaction equilibrium represents a state in which the rates of the forward and reverse reactions are equal. This means that, although reactions are occurring in both directions, there is no net change in the concentrations of reactants and products. The system is in a dynamic balance.
In the context of Le Chatelier's Principle, if an external change is applied to a system at equilibrium, the system will adjust to nullify that change. This could involve shifting the equilibrium to favor the forward or reverse reaction, depending on the change.
For the reactions involving carbon dioxide ( \(CO_2\) ), water ( \(H_2O\) ), carbonic acid ( \(H_2CO_3\) ), hydrogen ions ( \(H^+\) ), and bicarbonate ions ( \(HCO_3^{-}\) ), this principle means any change in the concentration of one component will affect the others. For example, removing \(CO_2\) will cause the equilibrium to shift left, forming more \(CO_2\) and moving away from forming more \(H^+\) and \(HCO_3^{-}\).
Carbonic Acid Equilibrium
Carbonic acid equilibrium is essential to understanding how our body regulates the balance between acids and bases. The compound \(H_2CO_3\) exists in equilibrium with carbon dioxide and water and can dissociate into hydrogen ions and bicarbonate ions. This balance plays a crucial role in numerous physiological processes.
When \(CO_2\) levels decrease, such as when it escapes from the body or system, the balance shifts to the left, as seen in the equation linked to our body's respiratory and metabolic pathways. This is a clear demonstration of how dynamic and vital this equilibrium is for maintaining the correct pH in our blood and other body fluids.
  • This equilibrium shift helps our body in:
    • Regulating blood pH
    • Balancing acid and base levels
pH and Hydrogen Ion Concentration
The concept of pH arises from the concentration of hydrogen ions ( \(H^+\) ) in a solution. A higher concentration of hydrogen ions indicates a lower pH, meaning the solution is more acidic. Conversely, a lower concentration of hydrogen ions results in a higher pH, indicating the solution is more alkaline.
In the reaction equilibrium involving carbonic acid, any change that affects the concentration of \(H^+\) ions will directly influence the pH. For instance, in scenarios where \(CO_2\) escapes and the equilibrium shifts left, the decrease in \(H^+\) concentration results in increasing pH levels.
Understanding this relationship is crucial, as it helps explain the body's response to fluctuations in carbon dioxide and how it maintains homeostasis through buffering systems and respiratory adjustments. It's a pivotal concept in physiology, chemistry, and when studying how organisms balance internal conditions.

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Most popular questions from this chapter

Which of the following statement is/are incorrect here? a. Equilibrium constant of an exothermic reaction decreases with the increase of temperature b. \(\mathrm{K}_{\mathrm{p}}\) is always greater than \(\mathrm{K}_{\mathrm{C}}\)

At \(298 \mathrm{~K}\) the value of ionization constant of anilinium hydroxide is \(4.6 \times 10^{-10}\) and that of ionic product of water \(1 \times 10^{-14}\), the value of degree of hydrolysis constant is nearly? a. \(0.415 \%\) b. \(4.15 \%\) c. \(0.163 \%\) d. \(0.217 \%\)

For the reaction, \(2 \mathrm{X}(\mathrm{g})+\mathrm{Y}(\mathrm{g}) \rightleftharpoons 2 \mathrm{Z}(\mathrm{g}), \Delta \mathrm{H}=+15.6 \mathrm{~kJ}\) Which of the following will increase the extent of the reaction at equilibrium? a. Addition of catalyst b. Increasing concentration of \(Z\) c. Increasing the temperature d. Increasing the pressure

Cyclohexane \(\left(\mathrm{C}_{6} \mathrm{H}_{12}\right)\) undergoes a molecular rearrangement in the presence of \(\mathrm{AlCl}_{3}\) to form methylcyclopentane (MCP) according to the equation: \(\mathrm{C}_{6} \mathrm{H}_{12} \rightleftharpoons \mathrm{MCP}\) If \(\mathrm{K}_{\mathrm{C}}=0.143\) at \(25^{\circ} \mathrm{C}\) for this reaction, predict the direction the reaction will shift, if the initial concentrations of \(\mathrm{C}_{6} \mathrm{H}_{12}\) and \(\mathrm{MCP}\) are \(0.200 \mathrm{M}\) and \(0.100 \mathrm{M}\), respectively. The system a. is already at equilibrium b. will shift right c. will shift left d. is not at equilibrium and will remain in an unequilibrated state.

\((\mathbf{A}):\) When \(0.1 \mathrm{M}\) diprotic weak acid \(\mathrm{H}, \mathrm{X}\) dissociates with its dissociation constants \(\mathrm{K}_{\mathrm{a}}=10^{-4}\) and \(\mathrm{K}_{\mathrm{a} 2}\) \(=10^{-12}\), then \(\left[\mathrm{X}^{-2}\right]\) is almost equal to \(10^{-12} \mathrm{M}\) \((\mathbf{R}):\) Since \(K_{a 2}<<\mathbb{K}_{a 1}\) for \(0.1 \mathrm{M}\) so \(\mathrm{H}_{2} \mathrm{X}\) so \(\left[\mathrm{X}^{-2}\right]\) is negligible w.r.t. \(\left[\mathrm{HX}^{-}\right]\). Hence \(\left[\dot{\mathrm{X}}^{-2}\right] \approx \mathrm{K}_{\mathrm{a} 2}\)

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