/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 191 \((\mathbf{A}):\) When \(0.1 \ma... [FREE SOLUTION] | 91影视

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\((\mathbf{A}):\) When \(0.1 \mathrm{M}\) diprotic weak acid \(\mathrm{H}, \mathrm{X}\) dissociates with its dissociation constants \(\mathrm{K}_{\mathrm{a}}=10^{-4}\) and \(\mathrm{K}_{\mathrm{a} 2}\) \(=10^{-12}\), then \(\left[\mathrm{X}^{-2}\right]\) is almost equal to \(10^{-12} \mathrm{M}\) \((\mathbf{R}):\) Since \(K_{a 2}<<\mathbb{K}_{a 1}\) for \(0.1 \mathrm{M}\) so \(\mathrm{H}_{2} \mathrm{X}\) so \(\left[\mathrm{X}^{-2}\right]\) is negligible w.r.t. \(\left[\mathrm{HX}^{-}\right]\). Hence \(\left[\dot{\mathrm{X}}^{-2}\right] \approx \mathrm{K}_{\mathrm{a} 2}\)

Short Answer

Expert verified
Yes, \([X^{2-}] \approx 10^{-12} \,M\) is correct for a 0.1 M diprotic acid solution.

Step by step solution

01

Identify the problem statement

We have a diprotic weak acid, H鈧俋, with dissociation constants \(K_{a1} = 10^{-4}\) and \(K_{a2} = 10^{-12}\). The task is to verify if \([X^{2-}]\) is approximately \(10^{-12} \,M\) for a \(0.1\,M\) solution of this acid.
02

Analyze the first dissociation

The first dissociation can be represented as \(\mathrm{H}_2\mathrm{X} \rightleftharpoons \mathrm{H}^+ + \mathrm{HX}^-\) with a dissociation constant \(K_{a1} = 10^{-4}\). This equilibrium shows that most of the \(\mathrm{H}_2\mathrm{X}\) remains undissociated due to the relatively small \(K_{a1}\) value.
03

Analyze the second dissociation

The second dissociation is \(\mathrm{HX}^- \rightleftharpoons \mathrm{H}^+ + \mathrm{X}^{2-}\) with \(K_{a2} = 10^{-12}\). \(K_{a2}\) is significantly smaller than \(K_{a1}\), indicating that the second dissociation (formation of \(\mathrm{X}^{2-}\)) occurs to a much lesser extent.
04

Establish relationship between concentrations

From the second dissociation, \([X^{2-}]\) depends mostly on the \(K_{a2}\) value. Because \(K_{a2} = 10^{-12}\) is much smaller compared to \(K_{a1}\), the concentration of \(X^{2-}\) will be approximately equal to \(K_{a2}\), considering that the concentration of \(\mathrm{HX}^-\) from the first dissociation is much higher.
05

Evaluate the given condition

According to the problem statement, \([X^{2-}]\) is almost equal to \(10^{-12} \,M\). Given the explanation in the previous step that \([X^{2-}] \approx K_{a2}\), the condition is justified and \([X^{2-}] \approx 10^{-12} \,M\) holds true for the given \(0.1\,M\) concentration of the diprotic acid.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dissociation Constants
Dissociation constants are values that help us understand how strongly an acid dissociates in a solution. When dealing with weak acids, these constants, usually denoted as \( K_a \), indicate the extent of acid ionization. For diprotic acids, which can release two hydrogen ions, there are two dissociation constants to consider: \( K_{a1} \) for the first release and \( K_{a2} \) for the second. Typically, in weak acids like H鈧俋, \( K_{a1} \) is considerably larger than \( K_{a2} \), meaning the first dissociation happens more readily than the second. This distinction significantly influences the concentration of ions formed in the solution. Understanding \( K_a \) values can predict how an acid behaves when it dissolves in water and how much it ionizes.
H2X Dissociation
H鈧俋 dissociation is the process by which the diprotic weak acid H鈧俋 breaks down in water. This acid first dissociates into an H鈦 ion and an HX鈦 ion.
  • The equation for this first dissociation is: \( ext{H}_2 ext{X} ightleftharpoons ext{H}^+ + ext{HX}^- \)
Since \( K_{a1} \) is \( 10^{-4} \), a moderate portion of H鈧俋 will dissociate, but much of it remains undissociated due to its weak acidic nature.
  • The second step of dissociation involves the HX鈦 ion releasing another hydrogen ion: \( ext{HX}^- ightleftharpoons ext{H}^+ + ext{X}^{2-} \)
In this case, \( K_{a2} \) is \( 10^{-12} \), greatly limiting the extent of the second dissociation. This means that small amounts of the X虏鈦 ion are formed in the solution. Understanding these dissociation steps is vital because it helps predict the ionic concentration in the solution, which is essential for various chemical calculations.
Acid Equilibrium
Acid equilibrium refers to the dynamic balance between the undissociated acid and the ions produced in solution. For weak acids like H鈧俋, the concept of equilibrium is crucial in determining concentrations of different species in the solution.
As H鈧俋 dissociates, it reaches a state where the rates of dissociation and recombination of ions are equal, establishing an equilibrium state. Here's what happens:
  • The forward reaction, where H鈧俋 loses protons to form H鈦 and HX鈦, becomes balanced by the reverse reaction, where these ions recombine to reform H鈧俋.
Even if the dissociation constants may suggest little dissociation occurs, in reality, the equilibrium allows for a certain balance of ions to be present in the solution.
With K鈧 values being so small, especially K鈧愨倐, most of the acid in such solutions remains as H鈧俋, with very little of it existing as the X虏鈦 ions.
Ka1 and Ka2 Differences
The difference between K鈧愨倎 and K鈧愨倐 in diprotic acids like H鈧俋 plays a significant role in understanding acid behavior. K鈧愨倎 is much greater than K鈧愨倐, which means the first dissociation step is more favorable. The impact of this is profound:
  • Most of the hydrogen ions come from the first dissociation.
  • The second dissociation barely contributes to the overall hydrogen ion concentration in the solution.
This large discrepancy in K鈧 values indicates why
  • X虏鈦 ions are found in minuscule amounts, equal approximately to K鈧愨倐.
  • In contrast, a more considerable concentration of HX鈦 ions exists due to the more favorable first dissociation process.
This understanding helps us predict and confirm observed experimental conditions, such as the negligible formation of X虏鈦 ions in the solution, which aligns with the given exercise's problem statement.

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