Chapter 25: Problem 7
The speed of sound in an ideal monatomic gas is given by $$u_{\text {sound }}=\left(\frac{5 R T}{3 M}\right)^{1 / 2}$$ Derive an equation for the ratio \(u_{\mathrm{rms}} / u_{\text {sound }^{*}}\) Calculate the root-mean-square speed for an argon atom at \(20^{\circ} \mathrm{C}\) and compare your answer to the speed of sound in argon.
Short Answer
Step by step solution
Understand the given formula
Recall the RMS speed formula
Derive the ratio \( u_{\text{rms}} / u_{\text{sound}} \)
Convert temperature to Kelvin
Calculate RMS speed for argon
Calculate speed of sound for argon
Compare RMS speed to sound speed
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ideal gas law
- \( P \) represents the pressure of the gas.
- \( V \) represents the volume of the gas.
- \( n \) is the number of moles of the gas.
- \( R \) is the universal gas constant, approximately equal to 8.314 J/(mol·K).
- \( T \) is the temperature, measured in Kelvin.
For our exercise of sound speed in a gas, only temperature \( T \) and the molar mass \( M \), which relates to the density \( \rho \), are crucial. The speed of sound depends on the medium's elasticity and inertial properties, with temperature playing a key role in understanding energy distribution among gas particles.
Root-mean-square speed
- \( u_{\text{rms}} \) denotes the root-mean-square speed.
- \( R \) is the universal gas constant.
- \( T \) is the absolute temperature in Kelvin.
- \( M \) symbolizes the molar mass of the gas.
Kinetic theory of gases
- Gases consist of a large number of tiny particles in constant motion.
- The volume of the individual gas particles is negligible compared to the gas's overall volume.
- No forces act on the particles except during elastic collisions.
- The kinetic energy of particles is proportional to the temperature of the gas.