/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q33P When it is strongly heated, meth... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

When it is strongly heated, methyl diazoacetate decomposes to give a nitrogen gas and a carbene. Draw a Lewis structure of the carbene.

Short Answer

Expert verified

Carbenes may be defined as a neutral divalent chemical species containing a carbon atom consisting six electrons in their valence shell. Out of six electrons, two electrons are unshared. The simplest carbene is methylene .

Step by step solution

01

Carbenes

Carbenes may be defined as a neutral divalent chemical species containing a carbon atom consisting six electrons in their valence shell. Out of six electrons, two electrons are unshared. The simplest carbene is methylene .

02

Lewis structures

The formation of covalent bond in molecules is shown in an easier way by Lewis structures. The valence electrons are represented by dots in the Lewis structure and one bond is represented as two electrons. In drawing Lewis structures, the atoms are arranged in such a way that all of them have eight valence electrons. The exception is with hydrogen, which can have a maximum of two valence electrons.

03

Decomposition of methyl diazoacetate to nitrogen and carbene

04

Lewis structure of carbene

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

For each compound, predict the major product of free-radical bromination. Remember that bromination is highly selective, and only the most stable radical will be formed.

(a) cyclohexane

(b) methylcyclopentane

(c) decalin

(d) hexane

(e)

(f)

Propionitrile()is deprotonated by very strong bases. Write resonance forms to show the stabilization of the carbanion that results.

(a) Draw an approximate reaction-energy diagram for the acid-base reaction of phenol (see below) with 1-molar aqueous sodium hydroxide solution.

(b) On the same diagram, draw an approximate reaction-energy diagram for the acid-base reaction oftert- butyl alcohol(see below) with 1-molar aqueous sodium hydroxide solution.

In the presence of a small amount of bromine, cyclohexene undergoes the following light-promoted reaction:

(a) Propose a mechanism for this reaction.

(b) Draw the structure of the rate-limiting transition state.

(c) Use Hammond’s postulate to predict which intermediate most closely resembles this transition state.

(d) Explain why cyclohexene reacts with bromine much faster than cyclohexane, which must be heated to react.

When healthy, Earth’s stratosphere contains a low concentration of ozone (O3)that absorbs potentially harmful ultraviolet (UV) radiation by the cycle shown at right.

Chlorofluorocarbon refrigerants, such as Freon 12 (CF2Cl2), are stable in the lower atmosphere, but in the stratosphere, they absorb high-energy UV radiation to generate chlorine radicals.

The presence of a small number of chlorine radicals appears to lower ozone concentrations dramatically. The following reactions are all known to be exothermic (except the one requiring light) and to have high-rate constants. Propose two mechanisms to explain how a small number of chlorine radicals can destroy large numbers of ozone molecules. Which of the two mechanisms is more likely when the concentration of chlorine atoms is very small?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.