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A small pilot was adding bromine across the double bond of but-2-ene to make 2,3-dibromobutane. A controller malfunction allowed the reaction temperature to rise beyond safe limits. A careful distillation of the product showed that several impurities had formed, including the one having the NMR spectra that appear below. Determine its structure and assign the peaks to the protons in your structure.

Short Answer

Expert verified

This structure has four different kinds of protons, thus will exhibit four signals in proton NMR.

The values of chemical shifts and splitting of peaks is,

a =4.3 (sextet,) c =2.3 (multiplet,)

b =3.6 (triplet,) d =1.7 (doublet,)

Step by step solution

01

Determination of structure:

There is no evidence present for vinyl hydrogens so the double bond cannot be present. Integration gives eight hydrogens, so the formula must be , and the four carbons must be in a straight chain because the starting material was but-2-ene. From the integration, four carbons must be present as one methyl, one methine, and two methylene groups. The methyl is split into doublet so it must be adjacent to the . The two methylene groups must follow in succession with two bromine atoms filling remaining vacancies. Thus, the structure would look like as follows

Structure derived from given NMR spectrum

02

Values of chemical shifts and splitting of peaks in structure determined:

The structure determined from NMR spectrum has four different kinds of protons, thus will exhibit four signals in proton NMR.

The values of chemical shifts and splitting of peaks is,

a =4.3 (sextet,) c =2.3 (multiplet,)

b =3.6 (triplet,) d =1.7 (doublet,)

Chemical shift values depends on electronegativity of nearby atoms and also whether the electron density is more or less around that proton whose chemical shift value we are determining. In the given structure, bromine is an electronegative atom, thus, protons-a and b will have higher chemical shift value than protons-c and d. Due to more electronegative atom present, region of low electron density or deshielded environment is created due to which chemical shift increases.

Different kinds of protons gives different values of chemical shifts

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Most popular questions from this chapter

The three isomers of dichlorobenzene are commonly named ortho-chlorobenzene, meta-chlorobenzene, and para-chlorobenzene. These three isomers are difficult to distinguish using proton NMR, but they are instantly identifiable using 13C NMR

(a)Describe how carbon NMR distinguishes these three isomers.
(b)Explain why they are difficult to distinguish using proton NMR.

Question:In a 300-MHz spectrometer, the protons in bromomethane absorb at a position 660 Hz downfield from TMS.

(a) What is the chemical shift of these protons?

(b) What is the chemical shift of the bromomethane protons in a 60-MHz spectrometer?

(c) How many hertz downfield from TMS would they absorb at 60 MHz?

  1. Show which carbon atoms correspond with which peaks in the 13CNMR spectrum of butan-2-one (Figure 13-45).
  2. Draw the proton NMR spectrum you would expect for butan-2-one. How well do the proton chemical shifts predict the carbon chemical shifts using the 鈥15 to 20 times as large鈥 rule of thumbs?

Question: How many signals would you expect to see in the 13CNMR of the following compounds? In each case, show which carbon atoms are equivalent in the 13CNMR.

The following spectra are taken from a compound that is an important starting material for organic synthesis. Determine the structure, first by considering each spectrum individually, and then by considering all the spectra together. Assign peaks to show that your proposed structure accounts for all the major features of each spectrum. DEPT information is given in blue on the carbon NMR

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