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Question. (a) Show how you would synthesize the pure (R) enantiomer of 2-pentyl methyl sulfide, starting with pure (R)-pentan-2-ol and any reagents you need.

(b) Show how you would synthesize the pure (S) enantiomer of the product, still starting with (R)-pentan-2-ol and any reagents you need.

Short Answer

Expert verified

(a)

(b)

Step by step solution

01

Step-1. Explanation of part (a):

(R)-pentan-2-ol on reaction with phosphorous tribromide undergoes substitution reaction in which bromide ion attacks as a nucleophile and displaces hydroxyl group, this reaction is SN2 in nature and thus, inversion takes place at the chiral center, that is, 鈥淩鈥 changes to 鈥淪鈥, and then on treatment with sodium methanethiloate, again SN2 reaction takes place and inversion occurs at the chiral center and 鈥淪鈥 configuration changes to 鈥淩鈥 configuration.

Formation of (R)-enantiomer of 2-pentyl methyl sulfide

02

Step-2. Explanation of part (b):

(R)-pentan-2-ol on reaction with tosyl chloride and pyridine undergoes acid-base reaction first, as pyridine acts as a base and abstracts proton from hydroxyl group, then, oxygen anion attacks at tosyl group and tosylate is formed. Configuration at chiral center do not changes. Then, on treatment with sodium methanethiloate, SN2 reaction takes place and inversion occurs at the chiral center and 鈥淩鈥 configuration changes to 鈥淪鈥 configuration.

Formation of (S)-enantiomer of 2-methyl pentyl sulfide

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Most popular questions from this chapter

Question. The 2001 Nobel Prize in Chemistry was awarded to three organic chemists who have developed methods for catalytic asymmetric synthesis. An asymmetric (or enantioselective) synthesis is one that converts an achiral starting material into mostly one enantiomer of a chiral product. K. Barry Sharpless (The Scripps Research Institute) developed an asymmetric epoxidation of allylic alcohols that gives excellent chemical yields and greater than 90% enantiomeric excess.

The Sharpless epoxidation uses tert-butyl hydroperoxide, titanium(IV) isopropoxide, and a dialkyl tartarate ester as the reagents. The following epoxidation of geraniol is typical.

  1. Which of these reagents is most likely to be the actual oxidizing agent? That is, which reagent is reduced in the reaction? What is the likely function of the other reagents?
  2. When achiral reagents react to give a chiral product, that product is normally formed as a racemic mixture of enantiomers. How can the Sharpless epoxidation give just one nearly pure enantiomer of the product?
  3. Draw the other enantiomer of the product. What reagents would you use if you wanted to epoxidize geraniol to give this other enantiomer?

Give a common name (when possible) and a systematic name for each compound

(a) CH3OCH=CH2

(b) CH3CH2OCH(CH3)2

(c) ClCH2CH2OCH3

(d)

e)

f)

g)

h)

i)

Propose a Williamson synthesis of 3-butoxy-1,1-dimethylcyclohexane from 3,3-dimethyl-cyclohexanol and butan-1-ol.

Question. Glycerol (propane-1,2,3-triol) is a viscous syrup with molecular weight 92g/mol, boiling point 290oC, and density 1.24g/mol. Transforming the three hydroxy groups into their trimethylsilyl ethers (using chlorotrimethylsilane and a tertiary amine) produces a liquid that flows easily, has molecular weight 309g/mol, boiling point approximately 180oC, and density 0.88g/mol. Draw the structures of these two compounds and explain why glycerol has a lower molecular weight but a much higher boiling point and density.

Predict the products of the following reactants. An excess acid is available in each case.

(a) Ethoxycyclohexane + HBr (b) tetrahydropyran + HI

(c) anisole ( methoxybenzene) + HBr

(d)

(e)

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