91影视

Treatment of hept-6-en-1-ol with ozone in the presence of dimethyl sulfide gives 6-hydroxyhexanal, which reacts with Tolle鈥檚 reagent and forms a carboxylate ion in the product.

Now, the former compound undergoes intramolecular cyclization in the presence of an acid that gives the desired compound.

The overall synthesis for the preparation of caprolactone is as follows:

Formation of caprolactone

Treatment of methoxybenzene with bromine molecule gives 1-Bromo-4-methoxybenzene, which further reacts with Mg in the presence of ether gives a Grignard product (4-methoxyphenyl) magnesium bromide).

Now, the formed compound (4-methoxyphenyl) magnesium bromide reacts with carbon dioxide gives 4-methoxy benzoic acid, which reacts with thionyl chloride gives 4-methoxybenzoyl chloride, which reacts with ammonia to form the desired compound.

The formation of p-methoxybenzamide is represented as follows:

Formation of p-methoxybenzamide

Treatment of (bromomethyl) benzene with a cyanide ion gives 2-phenyl acetonitrile. Now, the cyanide group undergoes reduction with lithium aluminum hydride and forms the desired compound.

The desired compound is formed by the following reaction as follows:

(bromomethyl) benzene 2-phenylacetonitrile 2-phenylethan-1-amine

Formation of 2-phenylethan-1-amine

Treatment of gallic acid with excess sodium hydroxide followed by the reaction with excess methyl iodide gives 3,4,5-tri methoxy benzoic acid.

Now, the carboxylic acid group in 3,4,5-tri methoxy benzoic acid undergoes reduction with lithium aluminum hydride gives (3,4,5-tri methoxyphenyl) methanol, which reacts with tosyl chloride in the presence of pyridine gives a tosylate in the product.

Now, the tosyl group reacts with cyanide ion and forms a new C-C bond in the product, which further reacts with lithium aluminum hydride and yields the desired compound.

The desired compound mescaline is formed by the following reactions as follows:

Formation of mescaline