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Without referring to the chapter, draw the chair conformation of

(a) 伪 -D-mannopyranose (the C2 epimer of glucose).

(b) 尾 -D-allopyranose (the C3 epimer of glucose.)

(c) 伪 -D-galactopyranose (the C4 epimer of glucose).

(d) N-formylglucosamine, glucose with C2 oxygen atom replaced by a formylated amino group.

Short Answer

Expert verified

(a) 伪 -D-mannopyranose (the C2 epimer of glucose).

(b) 尾 -D-allopyranose (the C3 epimer of glucose.)

(c) 伪 -D-galactopyranose (the C4 epimer of glucose).

(d) N-formylglucosamine, glucose with C2 oxygen atom replaced by a formylated amino group.

Step by step solution

01

A concept:

Pyranose is a six membered cyclic hemiacetal. For example, a six membered ring of glucose is known as glucopyranose. Sugars which have the common configuration like the arrangement of -H and -OH around carbon atoms are same except the carbon present at position or carbon number are known as epimers. For example, glucose and mannose are epimers of each other.

02

(a) α -D-mannopyranose (the C2 epimer of glucose).

A six membered ring of mannose is known as 伪 -D-mannopyranose. The chair conformation of is shown by the figure below.

03

(b) β -D-allopyranose (the C3 epimer of glucose.)

A six membered ring of allose is known as 尾 -D-allopyranose. The chair conformation of is shown by the figure below.

04

(c) α -D-galactopyranose (the C4 epimer of glucose).

A six membered ring of galactose is known as 伪 -D-galactopyranose. The chair conformation of is shown by the figure below.

05

(d) N-formylglucosamine, glucose with C2 oxygen atom replaced by a formylated amino group.

When the C2 oxygen atom of glucose is replaced by a formylated amino group, it forms N-formylglucosamine. The chair conformation of N-formylglucosamine. is shown by the figure below.

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Most popular questions from this chapter

Give an equation to show the reduction of Tollens reagent by maltose.

Does lactose mutarotate? Is it a reducing sugar? Explain. Draw the two anomeric forms of lactose.

Emil Fischer synthesized L-gulose, an unusual aldohexose that reduces to give D-glucitol. Suggest a structure for this L sugar, and show how L-gulose gives the same alditol as D-glucose. (Hint: D-Glucitol has -CH2OHgroups at both ends. Either of these primary alcohol groups might have come from reduction of an aldehyde.)

Some protecting groups can block two OH groups of a carbohydrate at the same time. One such group is shown here, protecting the 4-OH and 6-OH groups of 尾 -D-glucose.

(a) What type of functional group is involved in this blocking group?

(b) What did glucose react with to form this protected compound?

(c) When this blocking group is added to glucose, a new chiral center is formed. Where is it? Draw the stereoisomer that has the other configuration at this chiral center. What is the relationship between these two stereoisomers of the protected compound?

(d) Which of the two stereoisomers in part (c) do you expect to be the major product? Why?

(e) A similar protecting group, called an acetonide, can block reaction at the 2鈥 and 3鈥 oxygens of a ribonucleoside. This protected derivative is formed by the reaction of the nucleoside with acetone under acid catalysis. From this information, draw the protected product formed by the reaction.

a) Draw D-allose, the C3 epimer of glucose.

b) Draw D-talose, the C2 epimer of D-galactose.

c) Draw D-idose, the C3 epimer of D-talose. Now compare your answers with Figure 23-3.

d) Draw the C4 鈥渆pimer鈥 of D-xylose. Notice that this 鈥渆pimer鈥 is actually an L-series sugar, and we have seen its enantiomer. Give the correct name for this L-series sugar.

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