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Show how to synthesize the following amines from the indicated starting materials by reductive amination.

(a) benzylmethylamine from benzaldehyde

(b) N-benzylpiperidine from piperdine

(c) N-cyclohexylaniline from cyclohexanone

(d) cyclohexylamine from cyclohexanone

(e)

(f)

Short Answer

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(a)

(b)

(c)

(d)

(e)

(f)

Step by step solution

01

Reductive amination

The most useful method for synthesis of amines is the reductive amination. In this process, 10 or 20 alkyl group is added to the nitrogen atom. Generally, aldehyde is used to add 10 alkyl group and ketone is used to add 20 alkyl group.

02

Synthetic methodology

a.

Benzalhedyde combines with methylamine (a primary amine) to undergo a condensation process to form (E)-N-benzylidenemethanamine (a Schiff base) which on further reduction with LiAlH4 (lithium aluminum hydride) gives N-methyl-1-phenylmethanamine ( a secondary amine).



reaction a

b.

Benzalhedyde combines with piperidine (a secondary amine) to undergo a condensation process to form an iminium salt (1-benzylidenepiperidin-1-ium) which on further reduction with NaBH(OAc)3 (sodium triacetoxy borohydride)gives 1-benzylpiperidine ( a tertiary amine).



reaction b

c.

Cylohexanone combines with aniline (a primary amine) to undergo a condensation process to form N-cyclohexylideneaniline (a Schiff base) which on further reduction with LiAlH4 (lithium aluminum hydride) gives N-cyclohexylaniline ( a secondary amine).



reaction c

d.

Cylohexanone combines with hydroxylamine (zero alkyl groups) to undergo a condensation process to form cyclohexanone oxime which on further reduction with LiAlH4 (lithium aluminum hydride) gives cyclohexanamine ( a primary amine).



reaction d

e.

1-phenylpropan-2one combines with hydroxylamine (zero alkyl groups) to undergo a condensation process to form (Z)-1-phenylpropan-2-one oxime which on further reduction with LiAlH4 (lithium aluminum hydride) gives ±amphetamine or 1-phenylpropan-2-amine ( a primary amine).



reaction e

f.

Cyclopenatnone combines with piperidine (a secondary amine) to undergo a condensation process to form an iminium salt (1-cyclopentylidenepiperidin-1-ium) which on further reduction with NaBH(OAc)3 (sodium triacetoxy borohydride)gives 1-cyclopentylpiperidine ( a tertiary amine).




reaction f

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Most popular questions from this chapter

Basicity depends on availability of an electron pair to bond a proton. Correlate structural effects in these amines with their basicities.

(a) Explain this order:

Question. (a) Show how fragmentation occurs to give the base peak at m/z 58 in the mass spectrum of ethyl propyl amine (N-ethylpropan-1-amine), shown below.

(b) Show how a similar cleavage in the ethyl group gives an ion of m/z72.

(c) Explain why the peak at m/z 72 is much weaker than the one at m/z 58.

Show how you would accomplish the following synthetic conversions.

(a) benzyl bromide to benzylamine

(b) 1-bromo-2-phenylethane to 3-phenylpropan-1-amine

(c) pentanoic acid to pentan-1-amine

(d) pentanoic acid to hexan-1-amine

(e) (R)-2-bromobutane to (S)-butan-2-amine

(f) (R)-2-bromobutane to (S)-2-methylbutan-1-amine

(g) hexan-2-one to 1-amino-2-methylhexan-2-ol

Predict the products of the following reactions:

(a) ±ð³æ³¦±ð²õ²õ â¶Ä‰N±á3 â¶Ä‰+ â¶Ä‰Ph−CH2CH2CH2Br→

(b)1−bromopentane→(2)LiAlH4(3)H3O+(1)NaN3

(c)

(d) product â¶Ä‰from â¶Ä‰part â¶Ä‰c→heat

(e)

(f) product â¶Ä‰from â¶Ä‰part â¶Ä‰e→(3)heat(1)excessCH3I(2)Ag2O

(g)

(h)

(i)

(j) product â¶Ä‰from â¶Ä‰part â¶Ä‰i→(2)H3O+(1)LiAlH4

(k)

(l)

a) Guanidine (shown) is about as strong base as hydroxide ion. Explain why guanidine is a much stronger base than most other amines.

(b) Show why p-nitroaniline is a much weaker base (3 pKb units weaker) than aniline.

(c) Explain why N,N-2,6-tetramethylaniline (shown) is a much stronger base than N,N-dimethylaniline.

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