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Consider the following compounds that vary from nearly nonacidic to strongly acidic. Draw the conjugate bases of these compounds and explain why the acidity increases so dramatically with substitution by nitro groups.

Short Answer

Expert verified

The anions (conjugate bases) are stabilized by delocalization.

Step by step solution

01

Conjugate acid-base pair

The residual part of acid after losing a proton (H+) will have a tendency to accept a proton (H+). Therefore, it will behave as a base. These pairs of substances which differ from one another by a proton(H+) are known as conjugate acid-base pairs. Consider a general example of an acid:

02

Resonance structures

A single structural formula sometimes cannot explain all the properties of a compound that is given. In such cases, the compound may be represented by two or more structural formulae which differ from each other only in the arrangement of electrons. None of this structural formula alone can explain all the observed properties of the compound. The compound is then said to show resonance. The various structures are known as resonating structures. The true structure of the molecule is not represented by any of the resonating structures but is considered to be a resonance hybrid of the various resonating structures. Resonance delocalization is considered as a dominating effect in stabilizing the conjugate base.

03

Step 3: Ka and pKa

Kais known as the acid dissociation constant and its value indicates the relative strength of the acid. pKai s defined as the negative logarithm (base ) of Ka. Mathematically, pKa.= -logKa value of strong acids is usually zero or even negative while pKathe value of weaker acids are greater than 4.

04

Drawing conjugate bases of the compounds

Each compound reacts with a generic base to give the conjugate base.

05

Explanation

With the addition of nitro group, the pKavalue decreases drastically. The acidity increases with nitro group because the anions (conjugate bases) that are formed are more stabilized by delocalization and also, they have more resonance structures.

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Most popular questions from this chapter

Predict the products of the following acid-base reactions.

(a)

(b)

(c)

(d)

(e)

(f)

(g)

(h)

Question: Circle the functional groups in the following structures. State to which class (or classes) of compounds the structure belongs.

(a)

(b)

(c)

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(j)

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The preceding equation for the protonation of acetamide shows a hypothetical product that is not actually formed. When acetamide is protonated by a strong enough acid, it does not protonate on nitrogen, but at different basic site. Draw the structure of the actual conjugate acid of acetamide, and explain (resonance) why protonation occurs where it does rather than on nitrogen. Calculate the pKa of this conjugate acid.

The pKa of ascorbic acid (vitamin C, page 9) is 4.17 , showing that it is lightly more acidic than acetic acid (CH3COOH,pKa =4.74) .

(a)Show four different conjugate bases that would be formed by deprotonation of the four different OH groups in ascorbic acid.

(b) Compare the stabilities of these four conjugate bases, and predict which OH group of ascorbic acid is the most acidic.

(c) Compare the most stable conjugate base of ascorbic acid with the conjugate base of acetic acid, and suggest why these two compounds have similar acidities, even though ascorbic acid lacks the carboxylic acid (COOH ) group

Acetic acid can also react as a very weak base (pKb). Two different site son acetic acid might become protonated to give the conjugate acid. Draw both of these possible conjugate acids, and explain (resonance) why the correct one is stable. Calculate the pKaof this conjugate acid.

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