/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 54 Examine the \(\alpha\)-helix con... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Examine the \(\alpha\)-helix conformation. Are amino acid side chains arranged all inside the helix, all outside the helix, or randomly?

Short Answer

Expert verified
Answer: In the α-³ó±ð±ô¾±³æ conformation, amino acid side chains are arranged on the outside of the helix.

Step by step solution

01

Understanding the α-³ó±ð±ô¾±³æ conformation

The α-³ó±ð±ô¾±³æ is a common secondary structure in proteins, formed by hydrogen bonding between the backbone atoms of amino acids within a protein chain. This pattern results in a right-handed helix structure, with the carbonyl (C=O) group of each amino acid residue forming a hydrogen bond with the amide (NH) group of another amino acid situated about 3.6 residues away along the polypeptide chain.
02

Arrangement of the amino acid side chains

In the α-³ó±ð±ô¾±³æ structure, the amino acid side chains (R groups) are not involved in the hydrogen bonding, and they protrude outwards from the helix. This means that the side chains are not situated within the helix itself but externally, projecting to the outside of the helix.
03

Conclusion

In the α-³ó±ð±ô¾±³æ conformation, amino acid side chains are arranged on the outside of the helix. They are not located inside the helix or arranged randomly. This specific arrangement allows for the stabilization of the α-³ó±ð±ô¾±³æ structure through hydrogen bonding and provides space for potential interactions between side chains and other components of the protein or its surroundings.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

α-³ó±ð±ô¾±³æ
The α-³ó±ð±ô¾±³æ is one of the most common ways in which proteins fold themselves into secondary structures. Imagine a twisting staircase where each step represents a unit called an "amino acid residue." In the α-³ó±ð±ô¾±³æ, this "staircase" is right-handed, meaning it curls upwards to the right.
This shape comes about because of interactions within the protein's backbone. More specifically, it involves hydrogen bonds forming between certain atoms. These bonds occur primarily between the carbonyl group (C=O) of one amino acid and the amide group (NH) of another, four positions down the chain.
  • The α-³ó±ð±ô¾±³æ arrangement allows the protein to coil efficiently and compactly.
  • Each turn of the helix consists of about 3.6 amino acid residues.
This pattern of bonding and structure is quite stable and plays a crucial role in the integrity and function of the protein. While this structure is certainly chemically impressive, it's interesting to note that the α-³ó±ð±ô¾±³æ itself is all about the protein's backbone, not its side chains.
Amino Acid Side Chains
In the α-³ó±ð±ô¾±³æ structure, the focus is on how the backbone of the amino acids interacts through hydrogen bonds, but amino acid side chains (also referred to as R groups) have a different role. They are like arms that stretch out from the twisted helix toward the outside.
These side chains do not get involved in the hydrogen bond network that maintains the helix.
This external arrangement has several significant implications:
  • Side chains are exposed and free to interact with other molecules or parts of the protein.
  • Their exposure influences the protein's interaction with its environment and other biological molecules.
  • This arrangement helps determine the protein's biochemical properties.
By protruding out, these side chains can play a pivotal role in how the protein behaves and interacts in its biological context—whether that is binding to other molecules or contributing to the protein's solubility.
Hydrogen Bonding
Hydrogen bonding is a kind of attraction that keeps various formations inside proteins, like the α-³ó±ð±ô¾±³æ, stable and functional. Such bonds occur when a hydrogen atom is attracted to a highly electronegative atom—like oxygen or nitrogen—which is what's happening within the backbone of the α-³ó±ð±ô¾±³æ.
These critical attractions lead to the formation of the helix structure through repeated bonding:
  • A carbonyl group (C=O) of one amino acid bonds with the amide group (NH) of another, four residues farther along.
  • This sequence of bonding creates the stiff and spiral shape of the helix.
  • This highly organized pattern provides a stable framework which supports the protein's overall structure.
These bonds are crucial not only for stability but also for allowing the protein to maintain a precise shape needed for its specific function. Without hydrogen bonding, many three-dimensional structures of proteins would not be able to hold their form.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Denaturation of a protein is a physical change, the most readily observable result of which is loss of biological activity. Denaturation stems from changes in secondary, tertiary, and quaternary structure through disruption of noncovalent interactions including hydrogen bonding and hydrophobic interactions. Three common denaturing agents are sodium dodecyl sulfate (SDS), urea, and heat. What kinds of noncovalent interactions might each reagent disrupt?

2,4-Dinitrofluorobenzene, very often known as Sanger's reagent after the English chemist Frederick Sanger who popularized its use, reacts selectively with the \(N\)-terminal amino group of a polypeptide chain. Sanger was awarded the 1958 Nobel Prize for chemistry for his work in determining the primary structure of bovine insulin. One of the few persons to be awarded two Nobel Prizes, he also shared the 1980 award in chemistry with American chemists, Paul Berg and Walter Gilbert, for the development of chemical and biological analyses of DNA. Following reaction with 2,4-dinitrofluorobenzene, all amide bonds of the polypeptide chain are hydrolyzed, and the amino acid labeled with a 2,4-dinitrophenyl group is separated by either paper or column chromatography and identified. (a) Write a structural formula for the product formed by treatment of the \(N\)-terminal amino group with Sanger's reagent and propose a mechanism for its formation. (b) When bovine insulin is treated with Sanger's reagent followed by hydrolysis of all peptide bonds, two labeled amino acids are detected: glycine and phenylalanine. What conclusions can be drawn from this information about the primary structure of bovine insulin? (c) Compare and contrast the structural information that can be obtained from use of Sanger's reagent with that from use of the Edman degradation.

Draw a structural formula for the product formed when alanine is treated with the following reagents. (a) Aqueous \(\mathrm{NaOH}\) (b) Aqueous \(\mathrm{HCl}\) (c) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}, \mathrm{H}_{2} \mathrm{SO}_{4}\) (d) \(\left(\mathrm{CH}_{3} \mathrm{CO}\right)_{2} \mathrm{O}, \mathrm{CH}_{3} \mathrm{COONa}\)

The BOC-protecting group may be added by treatment of an amino acid with di- tert-butyl dicarbonate as shown in the following reaction sequence. Propose a mechanism to account for formation of these products.

Account for the fact that the isoelectric point of glutamine (pI 5.65) is higher than the isoelectric point of glutamic acid (pI 3.08).

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.