Chapter 10: Problem 133
Thiols are much more acidic than alcohols.
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Chapter 10: Problem 133
Thiols are much more acidic than alcohols.
These are the key concepts you need to understand to accurately answer the question.
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Secondary alcohols can be oxidized to ketones ussing either \(\mathrm{PCC}_{\mathrm{a}} \mathrm{or} \mathrm{H}_{2} \mathrm{CrO}_{4}\),
Alcohols can be converted to haloalkames by reaction with HC., HBr, and HI, or PBrs \(50 C l_{2}\) or SOBr?. \- The HX reactions work hest for tertiary alcohols, where they involve a carbocation intermediate. \- \(\mathrm{PBr}_{3,} \mathrm{SOCl}_{2}\), or \(\mathrm{SOBr}_{2}\) react well with secondary and primary alcohols. These reactions involve an \(\mathrm{S}_{\mathrm{s}} 2\) displacement, so irversion of stereochemistry is seen when the DII group is bonded to a chiral center.
Proton transfer to the OH group to form an oxconium ion (add a proton)
followed ly loss of \(\mathrm{H}_{2} \mathrm{O}\) (break a bond to give stable
molecules or ions) gives a \(2^{\text {" carbocation }}\) intermediate.
Miggration of a methyl group with its bonding pair of electrons from the
adjacent carbon to the positively charged carbon gives a more stable \(3^{\text
{" }}\) carbocation (1,2shift). Proton transfer from this intermediate to a
base, here shown as \(\mathrm{H}_{2} \mathrm{O}\), gives the ohserved product
(take a proton away).
Primsary alcohols are oxidized to aldehydes using \(\mathrm{PCC}\), a reagent that is not used in water, thereby precluding hydrate formation and any further oxidation.
An alternative method for the synthesis of bromoalkanes from primary and secondary alcohols is through the use of phosphorous tribromide, \(\mathrm{PBr}_{3}\) - This method of preparation of bromoalkanes takes place under milder conditions than treatment with HBr. Although rearrangement sometimes occurs with \(\mathrm{PBr}_{3}\), the extent is considerably less than that with HBr, expecially when the reaction mixture is kept at or helow \(0^{-} \mathrm{C}\).
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