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a. Draw the conjugate acid of each base: \(\mathrm{NH}_{3}, \mathrm{Cl}^{-},\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}=\mathrm{O}\). b. Draw the conjugate base of each acid: \(\mathrm{HBr}, \mathrm{HSO}_{4}^{-}, \mathrm{CH}_{3} \mathrm{OH}\).

Short Answer

Expert verified
a. Conjugate acids: \( \mathrm{NH}_{4}^{+}, \mathrm{HCl}, (\mathrm{CH}_{3})_{2}\mathrm{C}=\mathrm{OH}^{+} \). b. Conjugate bases: \( \mathrm{Br}^{-}, \mathrm{SO}_{4}^{2-}, \mathrm{CH}_{3}\mathrm{O}^{-} \).

Step by step solution

01

Identify the Conjugate Acid for Each Base

To find the conjugate acid of a base, you need to add an \( \text{H}^{+} \) ion. This means increasing the hydrogen count by one and adjusting the charge accordingly. 1. For \( \mathrm{NH}_{3} \): Adding \( \text{H}^{+} \), \( \mathrm{NH}_{3} \) becomes \( \mathrm{NH}_{4}^{+} \).2. For \( \mathrm{Cl}^{-} \): Adding \( \text{H}^{+} \), \( \mathrm{Cl}^{-} \) becomes \( \mathrm{HCl} \).3. For \( \left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}=\mathrm{O} \): Adding \( \text{H}^{+} \) to the oxygen atom makes it \( \left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}-\mathrm{OH}^{+} \).
02

Identify the Conjugate Base for Each Acid

To find the conjugate base of an acid, you need to remove a \( \text{H}^{+} \) ion. This means decreasing the hydrogen count by one and adjusting the charge accordingly. 1. For \( \mathrm{HBr} \): Removing \( \text{H}^{+} \), \( \mathrm{HBr} \) becomes \( \mathrm{Br}^{-} \).2. For \( \mathrm{HSO}_{4}^{-} \): Removing \( \text{H}^{+} \), \( \mathrm{HSO}_{4}^{-} \) becomes \( \mathrm{SO}_{4}^{2-} \).3. For \( \mathrm{CH}_{3} \mathrm{OH} \): Removing \( \text{H}^{+} \), \( \mathrm{CH}_{3} \mathrm{OH} \) becomes \( \mathrm{CH}_{3} \mathrm{O}^{-} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acid-Base Reactions
Acid-base reactions are fundamental chemical reactions that can involve the transfer of hydrogen ions (H鈦) between molecules. In these reactions, an acid donates a hydrogen ion to a base.

This transfer helps in forming the conjugate acid and base pairs. Understanding this concept is essential for identifying the outcome of these reactions.

The process involves two steps:
  • Identification of an acid and a base.
  • Exchange of H鈦 ions between them.
By following these steps, you can correctly identify the products of an acid-base reaction and how conjugate acids and bases relate to each other.

Simply put, when an acid loses an H鈦, it becomes its conjugate base. Conversely, when a base gains an H鈦, it becomes its conjugate acid. Recognizing this pattern aids in predicting the results and balancing equations in acid-base reactions.
Ammonia (NH3)
Ammonia (NH鈧) is a common and well-known base in the field of chemistry. It is composed of one nitrogen atom bonded to three hydrogen atoms.

Being a base, it has the capacity to accept a hydrogen ion (H鈦). Upon receiving an H鈦, ammonia transforms into its conjugate acid, known as ammonium ion (NH鈧勨伜).

This transformation is crucial because:
  • It demonstrates how a base interacts in an acid-base reaction.
  • The change helps in understanding the basic properties of ammonia.
  • It highlights the formation of a more stable ionic structure.
Additionally, ammonia鈥檚 ability to form NH鈧勨伜 showcases its role in various biological and industrial processes where acid-base equilibrium is significant. Ammonia鈥檚 basic nature and its conversion into a conjugate acid serve as a classic example in studying basic and acidic properties of substances.
Hydrogen Ion (H+)
The hydrogen ion, or H鈦, plays a central role in acid-base chemistry. It is essentially a proton and can transform chemical substances by its presence or absence.

In acidic solutions, H鈦 ions are released, which increases the acidic nature of the solution. In contrast, basic solutions accept H鈦 ions, either neutralizing or decreasing their effects.

The importance of H鈦 in reactions include:
  • Driving the conversion between acids and conjugate bases.
  • Facilitating the transition from bases to conjugate acids.
  • Being a determinant in the pH value of solutions.
Every time an acid donates an H鈦, it effectively leaves behind its conjugate base. Similarly, when a base accepts an H鈦, it becomes its conjugate acid. These processes underscore the core function of H鈦 as the pivotal player in defining and balancing acidity and basicity in chemical reactions.
Chemical Structures
Understanding chemical structures is key to grasping how acids and bases interact and form their conjugate pairs. Each molecule鈥檚 structure determines its ability to donate or accept protons in a reaction.

For example:
  • Ammonia (NH鈧) has a trigonal pyramidal shape, allowing it to accept an H鈦 to form NH鈧勨伜.
  • The structure of an acid such as HBr involves a hydrogen atom bonded to a bromine atom, facilitating the release of H鈦.
Visualizing these structures helps in understanding:
  • Where and how protons are exchanged during reactions.
  • The stability of the resulting conjugate acids and bases.
  • Predicting the behavior of these substances in different environments.
Comprehending chemical structures provides insights into the intrinsic properties of the substances. It helps simplify complex reactions, making it easier to predict and manipulate chemical interactions in both educational and practical applications.

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Most popular questions from this chapter

Draw the product formed when the Lewis acid \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2}\right)_{3} \mathrm{C}^{+}\) reacts with each Lewis base: (a) \(\mathrm{H}_{2} \mathrm{O} ;\) (b) \(\mathrm{CH}_{3} \mathrm{OH} ;\) (c) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{O}\); (d) \(\mathrm{NH}_{3}\); (e) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH}\).

Compounds like amphetamine that contain nitrogen atoms are protonated by the HCl in the gastric juices of the stomach, and the resulting salt is then deprotonated in the basic environment of the intestines to regenerate the neutral form. Write proton transfer reactions for both of these processes. Where is amphetamine likely to be absorbed by the body?

Classify each species as a Lewis acid, a Br酶nsted-Lowry acid, both, or neither. a. \(\mathrm{H}_{3} \mathrm{O}^{+}\) b. \(\mathrm{Cl}_{3} \mathrm{C}^{+}\) c. \(\mathrm{BCl}_{3}\) d. \(\mathrm{BF}_{4}\)

What is the conjugate acid of each base? a. \(\mathrm{H}_{2} \mathrm{O}\) b. \({ }^{-} \mathrm{NH}_{2}\) C. \(\mathrm{HCO}_{3}^{-}\) d. \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{NHCH}_{3}\) e. \(\mathrm{CH}_{3} \mathrm{OCH}_{3}\) f. \(\mathrm{CH}_{3} \mathrm{COO}^{-}\)

Which of the following bases are strong enough to deprotonate \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{C} \equiv \mathrm{CH}\left(\mathrm{p} K_{\mathrm{a}}=25\right)\), so that equilibrium favors the products: (a) \(\mathrm{H}_{2} \mathrm{O} ;\) (b) \(\mathrm{NaOH}\); (c) \(\mathrm{NaNH}_{2}\); (d) \(\mathrm{NH}_{3}\); (e) \(\mathrm{NaH}\); (f) \(\mathrm{CH}_{3}\) Li?

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