Chapter 7: Problem 14
The \(\mathrm{pH}\) of pure water at \(80^{\circ} \mathrm{C}\) will be: \((\mathrm{a})=7\) (b) \(<7\) (c) \(>7\) (d) None of these
Short Answer
Expert verified
The \\(\mathrm{pH}\\) of pure water at \\(80^{\circ} \, \mathrm{C}\\) will be \\<7\\.
Step by step solution
01
Understanding Pure Water at Different Temperatures
Pure water at any temperature is neutral, meaning it always maintains an equal concentration of hydrogen ions \(H^+\) and hydroxide ions \(OH^-\). However, the ionic product of water \(K_w\) changes with temperature, influencing the \(\mathrm{pH}\) scale.
02
Knowing Ion Product Constant
At \(25^{\circ} \, \mathrm{C}\), \(K_w\) is \(1.0 \times 10^{-14}\), where \(\mathrm{pH} = 7\). However, at higher temperatures, like \(80^{\circ} \, \mathrm{C}\), \(K_w\) increases, meaning more \(H^+\) and \(OH^-\) are formed in water, thus reducing \(\mathrm{pH}\).
03
Exploring the pH at 80°C
At \(80^{\circ} C\), \(K_w\) will be greater than \(1.0 \times 10^{-14}\). Therefore, \(10^{-7}\), which is the concentration of \(H^+\), becomes larger, making \(\mathrm{pH}\) less than 7 while water remains neutral.
04
Determine the Correct Option
Given the increased \(K_w\) at \(80^{\circ} C\), causing a decrease in \(\mathrm{pH}\), the correct option is (b) \(<7\) since this reflects the changed scale due to temperature effects.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ionic Product of Water
The ionic product of water, commonly represented as \( K_w \), is a crucial parameter in understanding the behavior of water at different temperatures. In its simplest form, \( K_w \) is the product of the concentrations of hydrogen ions \( H^+ \) and hydroxide ions \( OH^- \) in water:\[ K_w = [H^+][OH^-] \].At standard laboratory temperature, which is \( 25^{\circ}C \), \( K_w \) is approximately \( 1.0 \times 10^{-14} \). This value indicates that the concentration of \( H^+ \) and \( OH^- \) in pure water are each \( 1.0 \times 10^{-7} \), leading to a neutral \( \mathrm{pH} \) of 7.
- The equal concentrations of \( H^+ \) and \( OH^- \) keep water neutral.
- Even though \( K_w \) changes with temperature, neutrality remains because the ion concentrations are always balanced.
Temperature Effect on pH
Temperature has a significant effect on the \( \mathrm{pH} \) of water despite its neutrality. As temperature rises, the water molecules gain energy, which increases their ability to ionize.This results in higher concentrations of hydrogen ions \( H^+ \) and hydroxide ions \( OH^- \). Consequently, the ionic product of water \( K_w \) becomes larger than \( 1.0 \times 10^{-14} \) at standard conditions.When \( K_w \) is greater, the value of hydrogen ion concentration also increases, causing the \( \mathrm{pH} \) value to drop below 7. This means pure water will have a \( \mathrm{pH} \) less than 7 at temperatures like \( 80^{\circ}C \), but it is still neutral because the hydrogen ions and hydroxide ions are in equal amounts.
- Higher temperature leads to greater ionization of water.
- Increased \( H^+ \) implies a lower \( \mathrm{pH} \), but neutrality is maintained.
Neutral Water Concept
The concept of neutral water is foundational in chemistry, referring to a condition where the concentrations of hydrogen ions \( H^+ \) and hydroxide ions \( OH^- \) are equal. Generally, we equate this with a \( \mathrm{pH} \) of 7, but this is a temperature-dependent characteristic.In the context of temperature, neutrality adjusts based on \( K_w \). So, even at different temperatures, water remains neutral if \( [H^+] = [OH^-] \), even if \( \mathrm{pH} \) is less or more than 7.At \( 80^{\circ}C \), for instance, the \( \mathrm{pH} \) is less than 7. Pure water remains neutral because the increase in \( H^+ \) is matched by an increase in \( OH^- \), effectively balancing the solution.
- Neutral water means \( [H^+] = [OH^-] \).
- The \( \mathrm{pH} \) number alone doesn't dictate neutrality at varying temperatures.