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In the reaction \(\mathrm{H}_{2}+\mathrm{I}_{2} \rightleftharpoons 2 \mathrm{HI}\) at equilibrium, some \(\mathrm{I}_{2}\) is added. What happens to the equilibrium: (a) It gets shifted to the right (b) It remains unchanged (c) It gets shifted to the left (d) First (b) then (c)

Short Answer

Expert verified
(a) It gets shifted to the right.

Step by step solution

01

Identify the Change in the System

In the given equilibrium reaction \( \mathrm{H}_{2}+\mathrm{I}_{2} \rightleftharpoons 2 \mathrm{HI} \), additional \( \mathrm{I}_{2} \) is added. This change increases the concentration of one of the reactants \( \mathrm{I}_{2} \).
02

Apply Le Chatelier's Principle

According to Le Chatelier's Principle, if a change is imposed on a system at equilibrium, the system will adjust to counteract the imposed change and restore a new equilibrium. Adding more \( \mathrm{I}_{2} \) will cause the equilibrium to shift in the direction that reduces the concentration of \( \mathrm{I}_{2} \).
03

Determine the Direction of the Equilibrium Shift

To reduce the concentration of \( \mathrm{I}_{2} \), the equilibrium will shift to the right, converting more \( \mathrm{H}_{2} \) and \( \mathrm{I}_{2} \) into \( \mathrm{HI} \). This shift helps to re-establish equilibrium by consuming some of the added \( \mathrm{I}_{2} \).
04

Conclusion

The equilibrium shifts to the right when \( \mathrm{I}_{2} \) is added, increasing the amount of \( \mathrm{HI} \) until a new equilibrium is established.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Equilibrium Shift
In chemical reactions, an equilibrium shift occurs when changes are made to a system that is already in a state of equilibrium. When a system is at equilibrium, the forward and reverse reactions occur at the same rate, meaning the concentration of reactants and products stays constant over time. This is a delicate balance; even slight changes can disrupt it.
In the reaction of \[\mathrm{H}_{2} + \mathrm{I}_{2} \rightleftharpoons 2 \mathrm{HI}\], adding more \( \mathrm{I}_{2} \) changes the concentration of reactants, prompting an equilibrium shift. According to Le Chatelier's Principle, the system will adjust by shifting the equilibrium to counteract the change—in this case, producing more \( \mathrm{HI} \). This shift to the right consumes some of the added \( \mathrm{I}_{2} \), helping to restore a new balance.
Chemical Equilibrium
Chemical equilibrium is a state in a reversible reaction where the rate of the forward reaction equals the rate of the backward reaction. This results in stable concentrations of both reactants and products. Think of it as a balanced seesaw; if a change is introduced, the balance will tip slightly until adjustments bring it back to a new state of equilibrium.
When \( \mathrm{I}_{2} \) is added to the reaction system, it disrupts this equilibrium. The additional \( \mathrm{I}_{2} \) increases the concentration of this reactant, causing the equilibrium to shift. The system "wants" to consume the excess \( \mathrm{I}_{2} \) by converting more \( \mathrm{H}_{2} \) and \( \mathrm{I}_{2} \) into \( \mathrm{HI} \), thus bringing the system back to equilibrium.
  • Equilibrium does not mean equal concentrations but equal rates of forward and reverse reactions.
  • Adding \( \mathrm{I}_{2} \) increases the rate of the forward reaction until a new equilibrium is achieved.
Reaction Dynamics
Reaction dynamics explore how reactions progress and adjust under different conditions. In the context of a chemical equilibrium, understanding dynamics helps us see how a system responds to changes such as the addition of reactants, changes in pressure, or temperature variations. For our reaction between \( \mathrm{H}_{2} \) and \( \mathrm{I}_{2} \) to form \( \mathrm{HI} \), the dynamics are influenced by the extent of external changes.
When additional \( \mathrm{I}_{2} \) is added, the reaction dynamics shift as the system attempts to reduce its concentration by converting it into \( \mathrm{HI} \). This is a direct application of Le Chatelier's Principle, illustrating the dynamic nature of equilibrium as it responds to the imposed stresses. Overall, by understanding these dynamics, we can predict how altering different aspects of a reaction will affect its progress and equilibrium position. It highlights the system's innate tendency to adjust and maintain equilibrium even under disturbances.

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Most popular questions from this chapter

If a mixture containing 3 moles of hydrogen and 1 mole of nitrogen is converted completely into ammonia, the ratio of volumes of reactants and products at the same temperature and pressure would be: (a) \(2: 1\) (b) \(1: 2\) (c) \(1: 3\) (d) \(3: 1\)

At \(\mathrm{Kp}\) for the following reaction is 1 atm \(\mathrm{X}(\mathrm{g}) \rightleftharpoons \mathrm{Y}(\mathrm{g})+\mathrm{Z}(\mathrm{g})\) At equilibrium, \(50 \%\) of \(\mathrm{X}(\mathrm{g})\) is dissociated. The total pressure of the equilibrium system is ' \(\mathrm{P}\) ' atm. what is the partial pressure (in atm) of \(X(g)\) at equilibrium: (a) 1 (b) 4 (c) 2 (d) \(0.5\)

If equilibrium constant for the reaction: \(\mathrm{N}_{2}+3 \mathrm{H}_{2} \rightleftharpoons 2 \mathrm{NH}_{3}\) is \(\mathrm{K}_{\mathrm{c}}\), then the equilibrium con- stant for the reaction \(\mathrm{NH}_{3} \rightleftharpoons \frac{1}{2} \mathrm{~N}_{2}+\frac{3}{2} \mathrm{H}_{2}\) will be. (a) \(\frac{1}{\mathrm{~K}_{\mathrm{c}}}\) (b) \(\frac{1}{\mathrm{~K}^{2}}\) (c) \(\sqrt{K}_{c}\) (d) \(\frac{1}{\sqrt{K}_{c}}\)

Which of the following favours the backward reaction in a chemical equilibrium: (a) Decreasing the concentration of one of the reactants (b) Increasing the concentration of one of the reactants (c) Increasing the concentration of one or more of the products (d) Removal of at least one of the products at regular intervals

Which of the following reaction will be favoured at low pressure: (a) \(\mathrm{N}_{2}+3 \mathrm{H}_{2} \rightleftharpoons 2 \mathrm{NH}_{3}\) (b) \(\mathrm{H}_{2}+\mathrm{I}_{2} \rightleftharpoons 2 \mathrm{HI}\) (c) \(\mathrm{PCl}_{5} \rightleftharpoons \mathrm{PCl}_{3}+\mathrm{Cl}_{2}\) (d) \(\mathrm{N}_{2}+\mathrm{O}_{2} \rightleftharpoons 2 \mathrm{NO}\)

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