/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 30 Provide the formula for each of ... [FREE SOLUTION] | 91影视

91影视

Provide the formula for each of the following binary ionic compounds: (a) cuprous sulfide (b) ferrous phosphide (c) mercuric iodide (d) plumbic oxide

Short Answer

Expert verified
(a) Cu鈧係, (b) Fe鈧働鈧, (c) HgI鈧, (d) PbO鈧.

Step by step solution

01

Understand the Nomenclature

First, recognize the type of ions involved in each compound name. The names end in '-ous' or '-ic,' indicating the charge of the metal cation. '-ous' refers to a lower oxidation state, while '-ic' refers to a higher oxidation state for the metal. Additionally, identify the non-metal anion present.
02

Determine the Metal's Oxidation State

For (a) cuprous sulfide, 'cuprous' indicates copper with a +1 charge, Cu鈦. 'Ferrous' in (b) ferrous phosphide suggests iron with a +2 charge, Fe虏鈦. 'Mercuric' for (c) mercuric iodide shows mercury with a +2 charge, Hg虏鈦. 'Plumbic' in (d) plumbic oxide indicates lead with a +4 charge, Pb鈦粹伜.
03

Identify the Anion

Next, identify the anion associated with each compound. In (a) sulfide is S虏鈦, in (b) phosphide is P鲁鈦, in (c) iodide is I鈦, and in (d) oxide is O虏鈦.
04

Balance the Charges

When writing the formula, balance the charges of cations and anions to ensure the total charge of the compound is zero. These ionic compounds must be electrically neutral.
05

Formulate Each Compound

(a) Cuprous sulfide: Combine two Cu鈦 ions with one S虏鈦 ion, resulting in Cu鈧係. (b) Ferrous phosphide: Combine three Fe虏鈦 ions with two P鲁鈦 ions, leading to Fe鈧働鈧. (c) Mercuric iodide: Combine one Hg虏鈦 ion with two I鈦 ions, resulting in HgI鈧. (d) Plumbic oxide: Combine one Pb鈦粹伜 ion with two O虏鈦 ions, resulting in PbO鈧.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ionic Compound Nomenclature
Naming binary ionic compounds is crucial for correctly identifying chemical substances. The names of these compounds provide insight into the elements involved and their respective roles. When working with binary ionic compounds, it is important to understand the nomenclature, which typically consists of two parts: the name of the metal (cation) followed by the non-metal (anion) with an '-ide' suffix.

The naming also incorporates the Latin roots of certain elements. For example, 'cuprous' and 'cupric' refer to copper, while 'ferrous' and 'ferric' refer to iron. These suffixes ('-ous' and '-ic') help denote the different oxidation states a metal can exhibit. The '-ous' ending suggests a lower oxidation state, whereas '-ic' signifies a higher oxidation state. This is crucial for correctly identifying the formula of the compound. Understanding these nomenclature rules makes it easier to derive chemical formulas and ensures clarity when communicating findings in chemistry.
Oxidation States
Oxidation states are characterized by the charge an atom would have if all bonds were purely ionic. In the context of binary ionic compounds, the oxidation state helps determine how elements combine.

Metal cations like copper, iron, mercury, and lead can have multiple oxidation states. Their names are often followed by 'ous' or 'ic,' denoting their specific state. For instance:
  • Cuprous denotes copper with a +1 charge, whereas cupric indicates a +2 charge.
  • Ferrous involves iron with a +2 charge, while ferric relates to a +3 charge.
  • Mercuric corresponds to mercury with a +2 charge.
  • Plumbic represents lead with a +4 charge, in contrast to plumbous at +2.
Non-metal anions derived from the elemental base name come with a set negative oxidation state, such as sulfide (-2), phosphide (-3), iodide (-1), and oxide (-2).

Assigning correct oxidation states enables the precise balancing of charges and the formulation of accurate chemical equations.
Charge Balance
Charge balance is a key principle in the formation of binary ionic compounds. These compounds must be electrically neutral, meaning the total positive charge from cations must equal the total negative charge from anions.

To balance charges, consider the total number of each type of ion needed:
  • For cuprous sulfide, two Cu鈦 ions (+1 each) pair with one S虏鈦 ion. This results in the formula Cu鈧係, maintaining charge balance.
  • In ferrous phosphide, three Fe虏鈦 ions combine with two P鲁鈦 ions. The formula Fe鈧働鈧 arises from balancing the +6 from iron and -6 from phosphide.
  • Mercuric iodide is formed by two I鈦 ions with one Hg虏鈦 ion, creating HgI鈧. The charges +2 and -2 cancel each other.
  • Lastly, plumbic oxide requires one lead ion at +4 to pair with two O虏鈦 ions, which results in PbO鈧, achieving neutrality.
This balancing act ensures that the chemical formula respects the electroneutrality principle, a fundamental aspect of writing correct ionic compound formulas.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.