Chapter 7: Problem 30
Provide the formula for each of the following binary ionic compounds: (a) cuprous sulfide (b) ferrous phosphide (c) mercuric iodide (d) plumbic oxide
Short Answer
Expert verified
(a) Cu鈧係, (b) Fe鈧働鈧, (c) HgI鈧, (d) PbO鈧.
Step by step solution
01
Understand the Nomenclature
First, recognize the type of ions involved in each compound name. The names end in '-ous' or '-ic,' indicating the charge of the metal cation. '-ous' refers to a lower oxidation state, while '-ic' refers to a higher oxidation state for the metal. Additionally, identify the non-metal anion present.
02
Determine the Metal's Oxidation State
For (a) cuprous sulfide, 'cuprous' indicates copper with a +1 charge, Cu鈦. 'Ferrous' in (b) ferrous phosphide suggests iron with a +2 charge, Fe虏鈦. 'Mercuric' for (c) mercuric iodide shows mercury with a +2 charge, Hg虏鈦. 'Plumbic' in (d) plumbic oxide indicates lead with a +4 charge, Pb鈦粹伜.
03
Identify the Anion
Next, identify the anion associated with each compound. In (a) sulfide is S虏鈦, in (b) phosphide is P鲁鈦, in (c) iodide is I鈦, and in (d) oxide is O虏鈦.
04
Balance the Charges
When writing the formula, balance the charges of cations and anions to ensure the total charge of the compound is zero. These ionic compounds must be electrically neutral.
05
Formulate Each Compound
(a) Cuprous sulfide: Combine two Cu鈦 ions with one S虏鈦 ion, resulting in Cu鈧係.
(b) Ferrous phosphide: Combine three Fe虏鈦 ions with two P鲁鈦 ions, leading to Fe鈧働鈧.
(c) Mercuric iodide: Combine one Hg虏鈦 ion with two I鈦 ions, resulting in HgI鈧.
(d) Plumbic oxide: Combine one Pb鈦粹伜 ion with two O虏鈦 ions, resulting in PbO鈧.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ionic Compound Nomenclature
Naming binary ionic compounds is crucial for correctly identifying chemical substances. The names of these compounds provide insight into the elements involved and their respective roles. When working with binary ionic compounds, it is important to understand the nomenclature, which typically consists of two parts: the name of the metal (cation) followed by the non-metal (anion) with an '-ide' suffix.
The naming also incorporates the Latin roots of certain elements. For example, 'cuprous' and 'cupric' refer to copper, while 'ferrous' and 'ferric' refer to iron. These suffixes ('-ous' and '-ic') help denote the different oxidation states a metal can exhibit. The '-ous' ending suggests a lower oxidation state, whereas '-ic' signifies a higher oxidation state. This is crucial for correctly identifying the formula of the compound. Understanding these nomenclature rules makes it easier to derive chemical formulas and ensures clarity when communicating findings in chemistry.
The naming also incorporates the Latin roots of certain elements. For example, 'cuprous' and 'cupric' refer to copper, while 'ferrous' and 'ferric' refer to iron. These suffixes ('-ous' and '-ic') help denote the different oxidation states a metal can exhibit. The '-ous' ending suggests a lower oxidation state, whereas '-ic' signifies a higher oxidation state. This is crucial for correctly identifying the formula of the compound. Understanding these nomenclature rules makes it easier to derive chemical formulas and ensures clarity when communicating findings in chemistry.
Oxidation States
Oxidation states are characterized by the charge an atom would have if all bonds were purely ionic. In the context of binary ionic compounds, the oxidation state helps determine how elements combine.
Metal cations like copper, iron, mercury, and lead can have multiple oxidation states. Their names are often followed by 'ous' or 'ic,' denoting their specific state. For instance:
Assigning correct oxidation states enables the precise balancing of charges and the formulation of accurate chemical equations.
Metal cations like copper, iron, mercury, and lead can have multiple oxidation states. Their names are often followed by 'ous' or 'ic,' denoting their specific state. For instance:
- Cuprous denotes copper with a +1 charge, whereas cupric indicates a +2 charge.
- Ferrous involves iron with a +2 charge, while ferric relates to a +3 charge.
- Mercuric corresponds to mercury with a +2 charge.
- Plumbic represents lead with a +4 charge, in contrast to plumbous at +2.
Assigning correct oxidation states enables the precise balancing of charges and the formulation of accurate chemical equations.
Charge Balance
Charge balance is a key principle in the formation of binary ionic compounds. These compounds must be electrically neutral, meaning the total positive charge from cations must equal the total negative charge from anions.
To balance charges, consider the total number of each type of ion needed:
To balance charges, consider the total number of each type of ion needed:
- For cuprous sulfide, two Cu鈦 ions (+1 each) pair with one S虏鈦 ion. This results in the formula Cu鈧係, maintaining charge balance.
- In ferrous phosphide, three Fe虏鈦 ions combine with two P鲁鈦 ions. The formula Fe鈧働鈧 arises from balancing the +6 from iron and -6 from phosphide.
- Mercuric iodide is formed by two I鈦 ions with one Hg虏鈦 ion, creating HgI鈧. The charges +2 and -2 cancel each other.
- Lastly, plumbic oxide requires one lead ion at +4 to pair with two O虏鈦 ions, which results in PbO鈧, achieving neutrality.